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lora16 [44]
2 years ago
13

A number,n,is added to 15 less than 3 times itself.result is 101. Wich equation can be used to find the value of x

Mathematics
1 answer:
noname [10]2 years ago
3 0

Let the number be 'x'

According to the question,

A number is added to 15 less than 3 times itself.

So,  x + (15 less than 3 times itself)

15 less than 3 times itself = 3x - 15

Now,  x + (15 less than 3 times itself) = x + (3x-15)

We get the result as 101.

So, x+ 3x-15 = 101

4x - 15 = 101

Therefore, it is the required equation used to evaluate the number 'x'.

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Answer:

D) n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3

Step-by-step explanation:

The given polynomial is 8mn^5  -2m^6 +5m^2 n^4 - m^3 n^3 + n^6 - 4m^6 + 9m^2n^4 -mn^5 - 4m^3n^3

Now we have to identify the like terms and simplify.

Like terms are nothing but the terms which have the same variables with same powers.

= (8mn^5 - mn^5) -2m^6 - 4m^6 + 5m^2 n^4 + 9m^2 n^4 - m^3n^3 - 4m^3n^3 +n^6

Now combine the like terms

= 7mn^5 - 6m^6 +14m^2 n^4-5m^3n^3 + n^6

It can be written in standard form

= n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3

The answer is D)

Hope this will helpful.

Thank you.

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Answer with explanation:

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