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2 years ago

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Ted likes to run long distances. He can run 20 \text{ km}20 km20, start text, space, k, m, end text in 959595 minutes. He wants

to know how many kilometers (k)(k)left parenthesis, k, right parenthesis he will go if he runs at the same pace for 285285285 minutes.

1 answer:

Ghella [55]2 years ago

5 0

Answer:

im looking for the anwser

Step-by-step explanation:

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Which data display shows the number of observations? Check all that apply.

Leno4ka [110]

Answer: A,C,E

Step-by-step explanation:

I took the test and got it right

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2 years ago

Read 2 more answers

In the diagram, points A, B, and C lie on a circle. Which conclusion can be correctly drawn from the fact that O is the center o

kolezko [41]

Answer:

Option D is correct

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2 years ago

Q1: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.

marin [14]

Answer:

C. hyperbola; $9x^2-25y^2-250y-850=0$

Step-by-step explanation:

The given conic has equation:

$9x^2-25y^2=225$

Divide through by 225.

$\frac{9x^2}{225}-\frac{25y^2}{225}=\frac{225}{225}$

$\frac{x^2}{25}-\frac{y^2}{9}=1$

This is a hyperbola centered at the origin.

The hyperbola has been translated from the origin to (0,5).

The translated hyperbola will have equation;

$\frac{(x-0)^2}{25}-\frac{(y-5)^2}{9}=1$

Multiply through by 225.

$9(x-0)^2-25(y-5)^2=225$

Expand

$9x^2-25(y^2-10y+25)=225$

$9x^2-25y^2+250y-625=225$

Rewrite in general form;

$9x^2-25y^2+250y-625-225=0$

$9x^2-25y^2+250y-850=0$

3 0

2 years ago

How many distinct pairs of disjoint non-empty subsets of A are there, the union of which is all of A?

Mrac [35]

A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8}
{2} U {1, 5, 6, 8}
{5} U {1, 2, 6, 8}
{6} U {1, 2, 5, 8}
{8} U {1, 2, 5, 6}
{1, 2} U {5, 6, 8}
{1, 5} U {2, 6, 8}
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6}
{1, 2, 5} U {6, 8}
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5}
The answer is 15 distinct pairs of disjoint non-empty subsets.

5 0

2 years ago

. According to Management Accounting, salary figures for certified management accountants (CMAs) who are in the field less than

Mice21 [21]

Answer:

The Mean is not equal to $31,129.

Step-by-step explanation:

Consider the provided information.

The mean is $31129

Thus, the null hypothesis $H_0: \mu = 31129$

Alternative hypothesis $H_a: \mu \neq 31129$

A random sample of 15 firstyear CMAs in Denver produces a mean salary of $32,279, with a standard deviation of $1,797.

Thus the value mean of sample is 32279, standard deviation is 1797 and number of samples are 15.

Now use the 2 sided t-test.

$t=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

Now substitute the respective values in the above formula.

$t=\frac{32279-31129}{\frac{1797}{\sqrt{15}}}$

$t=\frac{1150}{464}$

Test Value = 2.4785 approximately

Now, find the corresponding p-value in your t-table with DF(degree of freedom) 14.

p = 0.0265

as the value of p < 0.05, so you reject null hypothesis.

Thus, the Mean is not equal to $31,129.

7 0

2 years ago