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2 years ago

Round off 3409725 to nearest 10

Mathematics

1 answer:

Klio2033 [76]2 years ago

8 0

Answer:

10000

Step-by-step explanation:

to know if this answer is correct you have to know the rounding rules:

If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up. Example: 38 rounded to the nearest ten is 40.

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down. Example: 33 rounded to the nearest ten is 30.

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140 fluid ounces increased by 45%

Leokris [45]

First divided 140 by 100 to find out how much 1 percent is
140 ÷ 100 = 1.4

multiply 1.4 by 45 to find 45 %; 1.4 x 45 = 63

then add 63, which is 45%, to 140, which is 100%, and you get 203, which is 140 + 45%, or 145%

please mark brainliest if this helped you. I hope it did!

4 0

2 years ago

If you are one of the first 100 people to join a new health club, you are charged a joining fee of $49. Otherwise, you are charg

Drupady [299]

Answer:

a) Total cost = 49 + 38.75m

b) Total cost = 149 + 38.75m

c) The graphs of the lines are parallel and both has slope of - 2.5

d)Difference in total cost = $132.5

Step-by-step explanation:

Total cost , TC = Initial membership fee + monthly charges

a) TC = 49 + 38.75m

b)TC = 149 + 38.75m

d) 149 + 38.75(6months) = 381.5

49 + 38.75(12months) = 514

Difference in total cost = 514 -381.5 = $132.5

7 0

2 years ago

A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random

Harlamova29_29 [7]

Answer with explanation:

Given : Sample mean = $\overline{x}=\text{48.47 pounds}$

Standard deviation : $\sigma=\text{ 3.1 pounds.}$

Sample size : n = 36

Claim : $\mu\neq50$

∴ $H_0:\mu=50$

$H_1:\mu\neq50$

Since the alternative hypothesis is two tail , then the test is two tail test.

By using a z statistic and a 0.05 level of significance. Reject $H_0$ if z < -1.960 or is z> 1.960.

Then , the test static for population mean is given by :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$z=\dfrac{48.47-50}{\dfrac{3.1}{\sqrt{36}}}\approx-2.96$

We reject $H_0$ since $-2.96\leq -1.96$ . We have statistically significant evidence at $\alpha=0.05$ to show that the mean amount of garbage per bin is not different from 50.