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alexdok [17]
2 years ago
14

Suppose, instead, that Bruce used 6 full boxes of tiles plus an additional 2 tiles, and Felicia used 5 full boxes of tiles plus

an additional 17 tiles.
If they each used the same number of tiles, how many tiles were in each box?
Mathematics
2 answers:
Kitty [74]2 years ago
6 0

Answer: there were 15 tiles in each box

Step-by-step explanation:

Let the number of tiles in each full box be x

Suppose, instead, that Bruce used 6 full boxes of tiles plus an additional 2 tiles. It means that he used a total of

(6x + 2) tiles

Suppose, that Felicia used 5 full boxes of tiles plus an additional 17 tiles. It means that he used a total of

(5x + 2) tiles.

If they each used the same number of tiles, it means that the total number of tiles used by Bruce = total number of tiles used by Felicia. Therefore,

6x + 2 = 5x + 17

6x - 5x = 17 - 2

x = 15

Gnoma [55]2 years ago
5 0

Answer:

there were 15 tiles in each box

Step-by-step explanation:

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3. A CD costs £9.50 in London and
adelina 88 [10]

Step-by-step explanation:

Only Q4 has clear details

therefore, solving Question 4,

1 euro = $1.17

then,  €20.46 =20.46×1.17 = $23.93.

1 pound =1.28 dollars.

then,  £12.60 = 12.60×1.28 =$16.128

therefore, MP3 in pound is cheaper in dollar by $7.81.

6 0
2 years ago
A new drug on the market is known to cure 30% of patients with cervical cancer. If a group of 18 patients is randomly selected,
Dima020 [189]

Answer:

Probability cured of cervical cancer =  18C0 (0.30)⁰(0.70)¹⁸ +  18C1(0.30)(0.70)¹⁷

Step-by-step explanation:

Given:

Patients cured = 30% = 0.30

Number of patients (n) = 18

Probability cured of cervical cancer = P(X≤1)

Probability cured of cervical cancer  = P(X=0) + P(X=1)

Probability cured of cervical cancer =  18C0 (0.30)⁰(0.70)¹⁸ +  18C1(0.30)(0.70)¹⁷

5 0
1 year ago
Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be model
ohaa [14]

Answer:

(2, 11/2)

Step-by-step explanation:

This is a vertical parabola; we know that because x is squared here, while y is not.  The standard equation of a vertical parabola with vertex (h,k) is

4p(y-k) = (x-h)^2, where p is the distance between the vertex and the focus.  Comparing

4p(y-k) = (x-h)^2 to

10(y-3)  = (x-2)^2, we see that 4p = 10.  Therefore, p = 10/4 = 5/2, which is the vertical distance between the focus and the vertex.

Since the coordinates of the vertex are easily read from the given equation

(x-2)^2=10(y-3):  (h,k) = (2, 3)

all we need to do is to add p (5/2) to the y-coordinate (3);

The focus is at (2, 3 + 5/2), or (2, 11/2).

3 0
1 year ago
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
1 year ago
Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. The results in the screen disp
e-lub [12.9K]

Answer:

D. is the correct answer, hope this helps!


4 0
1 year ago
Read 2 more answers
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