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2 years ago

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A student theater charges $9.50 per ticket. The theater has already sold 70 tickets. Write and solve an inequality that represen

ts how many more tickets the theater needs to earn at least $1000.

1 answer:

Genrish500 [490]2 years ago

8 0

9.50 times 70 is greater or less than 1000

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Students in three levels of art classes participated in the regional art competition. The two-way table below shows the number o

irinina [24]

The relative frequencies, from least to greatest, would be:

The percentage of all entries painted by Art 1 students (14.33%), the percentage of Art 2 entries that were digital (22.02%), and the percentage of clay entries done by Art 3 students (25.32%).

Explanation
The percentage of clay entries done by Art 3 students: There are 20 clay entries done by Art 3 students, out of 79 clay entries; 20/79 = 25.32%

The percentage of all entries painted by Art 1 students: There are 43 entries painted by Art 1 students out of 300 total; 43/300 = 14.33%

The percentage of Art 2 entries that are digital: There are 24 Art 2 digital entries out of 109 total Art 2 entries; 24/109 = 22.02%

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2 years ago

Read 2 more answers

Suppose there are 500 units of energy available at the base of a pyramid of energy. How many units of that energy will the first

Ede4ka [16]

Answer:

With every other lever 10% of the energy with be transferred. In this case: Primary Producers (500) 1) First- level consumer. (50) 2) Second-level consumer. (5) 3) Third- level consumer. (0.5) Remember the formula is:(Primary Producer) __units X 10%= __500 units X 10%= 50

50 units of energy will be the first level consumers stored.

5 units of energy will be the second level consumers stored.

Step-by-step explanation:

3 0

1 year ago

A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is

MakcuM [25]

Answer:

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 5 minutes

Sample mean, $\bar{x}$ = 4.61 minutes

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.75 minutes

a) First, we design the null and the alternate hypothesis

$H_{0}: \mu = 5\text{ minutes}\\H_A: \mu \neq 5\text{ minutes}$

We use two-tailed t test to perform this hypothesis.

b) Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{4.61 - 5}{\frac{0.75}{\sqrt{15}} } = -2.0139$

c) Now, we calculate the p-value using the standard table.

P-value = 0.0638

d) Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Option a) Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05.

4 0

1 year ago

Lavania is studying the growth of a population of fruit flies in her laboratory. After 6 days she had nine more than five times

MatroZZZ [7]

Answer:

Lavania observed 39 fruit flies after 6 days of observation

Step-by-step explanation:

Let x be the number of fruit flies on the first day of Lavania's study.

After 6 days she had nine more than five times as many fruit flies as when she began the study.

Five times as many fruit flies as when she began the study = 5x

Nine more than five times as many fruit flies as when she began the study=5x+9

The expression to find the population of fruit flies Lavania observed after 6 days is 5x+9

If she observes 20 fruit flies on the first day of the study, then x=6, then

$5x+9=5\cdot 6+9=30+9=39$

5 0

1 year ago

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3

butalik [34]

Answer:

The answer is below

Step-by-step explanation:

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3 miles.

a) Start by drawing a diagram of this situation. Your diagram might include a coordinate plane, the cell tower, and a circle representing the cell tower's coverage boundary.

a) A house is located 5 miles north of the center of the town and is to the east of the cell tower. If the house lies on the boundary of the cell tower's coverage, how far east of the center of the town is the house?

Answer:

Let the center of the town represent the origin (0,0). Also 1 unit = 1 mile. Since the cell tower is located 3 miles east and 4 miles north of the center of a small town, it is represented by A(3, 4)

The cell tower has a coverage of radius 3 miles. This can be represented by a circle with equation:

(x - a)² + (y - b)² = r². where (a,b) is the center of the circle and r is the radius. Hence:

(x - 3)² + (y - 4)² = 3²

(x - 3)² + (y - 4)² = 9

The diagram is drawn using geogebra.

b) The house is 5 miles north. It can be represented by y = 5 line.

To find the distance east of the house we have to substitute y = 5 and solve for x, hence:

(x - 3)² + (y - 4)² = 9

(x - 3)² + (5 - 4)² = 9

(x - 3)² + 1 = 9

(x - 3)² = 8

(x - 3) = √8

x - 3 = ±2.83

x = 3 ± 2.83

x = 5.83 or 1.83

Since it is to the east to the cell tower, hence x = 5.83.

Therefore the house is located 5.83 miles to the east of the cell tower

8 0

2 years ago