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2 years ago

Find the dicontinuities of the function. f(x) = x2 + 12x + 27 x2 + 4x + 3 . There is a removable discontinuity at (, ).

Mathematics

2 answers:

ollegr [7]2 years ago

5 0

Answer:

Step-by-step explanation:

its -3 -3 for both

ValentinkaMS [17]2 years ago

4 0

Solution-

$f(x)=\frac{x^{2}+12x+27 }{x^{2} +4x+3} =\frac{x^{2}+9x+3x+27 }{x^{2} +3x+x+3}=\frac{(x+3)(x+9)}{(x+3)(x+1)}$

Equating the denominator to 0,

⇒ (x+3)(x+1) = 0

⇒ x= -3, -1

∴ Discontinuities of the function f(x) is at -3, -1

As (x+3) is also a factor of the numerator, you will have what's called a removable discontinuity. That will show up as a hole in the graph.

∴ At x = -3, you will have removable discontinuity.

You might be interested in

Using a 16-sided number cube, what is the probability that you will roll a multiple of 4 or an odd prime number? The number 1 is

iogann1982 [59]

<h3>Answer: 0.563 (choice C)</h3>

================================================

Explanation:

E = event space

E = set of outcomes we want to happen

E = rolling a multiple of 4 or rolling an odd prime number

E = {4,8,12,16 3,5,7,11,13}

n(E) = number of items in set E

n(E) = 9, (four multiples of 16+five ways to roll odd prime number)

-----

S = sample space

S = set of all possible outcomes (whether we want them to happen or not)

S = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}

n(S) = number of items in set S

n(S) = 16

-----

P(E) = probability of event space occurring

P(E) = probability of rolling a multiple of 4 or rolling an odd prime number

P(E) = n(E)/n(S)

P(E) = 9/16

P(E) = 0.5625

P(E) = 0.563

3 0

2 years ago

The length of time a full length movie runs from opening to credits is normally distributed with a mean of 1.9 hours and standar

Llana [10]

Answer:

a) The probability that a random movie is between 1.8 and 2.0 hours = 0.2586.

b) The probability that a random movie is longer than 2.3 hours is 0.0918.

c) The length of movie that is shorter than 94% of the movies is 1.4 hours

Step-by-step explanation:

In the above question, we would solve it using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation

a) A random movie is between 1.8 and 2.0 hours

z = (x-μ)/σ,

x1 = 1.8,

x2 = 2.0

μ is the population mean = 1.9

σ is the population standard deviation = 0.3

z1 = (1.8 - 1.9)/0.3

z1 = -1/0.3

z1 = -0.33333

Using the z score table

P(z1 = -0.33) = 0.3707

z2 = (2.0 - 1.9)/0.3

z1 = 1/0.3

z1 = 0.33333

p(z2 = 0.33) = 0.6293

= P(- 0.33 ≤ z ≤ 0.33)

= 0.6293 - 0.3707

= 0.2586

The probability that a random movie is between 1.8 and 2.0 hours = 0.2586

b) A movie is longer than 2.3 hours

z = (x-μ)/σ,

x1 = 2.3

μ is the population mean = 1.9

σ is the population standard deviation = 0.3

z = (2.3 - 1.9)/0.3

z = 4/0.3

z = 1.33333

P(z = 1.33) = 0.90824

P(x>2.3) = = 1 - 0.90824

= 0.091759

≈ 0.0918

The probability that a random movie is longer than 2.3 hours is 0.0918.

3) The length of movie that is shorter than 94% of the movies.

z = (x-μ)/σ

Probability (z ) = 94% = 0.94

Movie that is shorter than 0.94

= P(1 - 0.94) = P(0.06)

Finding the P (x< 0.06) = -1.555

≈ -1.56

μ is the population mean = 1.9

σ is the population standard deviation = 0.3

-1.56 = (x - 1.9)/ 0.3

Cross multiply

-1.56 × 0.3 = x - 1.9

- 0.468 + 1.9 = x

= 1.432 hours

≈ 1.4 hours

Therefore, the length of movie that is shorter than 94% of the movies is 1.4 hours

5 0

2 years ago

A stereo manufacturer makes three types of stereo systems, I, II, and III, with profits of $20, $30, and $40, respectively. No m

romanna [79]

So,

1. Type I profits $20
2. Type II profits $30
3. Type III profits $40
4. I/day < 100
5. Type I needs 5 hrs.
6. Type II needs 10 hrs.
7. Type III needs 15 hrs.
8. Total hrs. available: 2000 hrs.

Every +5 hrs. spent yields an extra $10.
If we use 500 hrs. to make 100 Type I stereos, we will profit $2000.
If we use 500 hrs. to make 50 Type II stereos, we will profit $1500.
If we use 495 hrs. to make 33 Type III stereos, we will profit $1320.

We should use the first 500 hrs. to make Type I stereos.
We should use the last 1500 hrs. to make Type II stereos.

$2000 + $4500 = x
$6500 = x

There must be 100 Type I stereos made along with 150 Type II stereos made.

4 0

2 years ago

Which sets of numbers contain whole numbers? Check all that apply. Negative 2 and StartFraction 5 Over 6 EndFraction, negative 5

Zigmanuir [339]

Answer:

The whole numbers are 0 and 79.

Step-by-step explanation:

The numbers provided are as follows:

$-2\frac{5}{6},\ -54,\ -4,\ -57,\ -89,\ 79,\ \frac{6}{9},\ \\\\-19\frac{2}{3},\ \frac{2}{4},\ 0,\ \frac{2}{7},\ -3,\ -2, -7,\ -8,\ \\\\\frac{1}{8},\ -\frac{4}{8},\ 1\frac{3}{8},\ -\frac{7}{8}$

Whole numbers are a set of natural positive numbers and 0. This set basically consists of counting discrete numbers.

Such as: 0, 1, 2, 3, 4, 5....

From the provided set of numbers the whole numbers are:

S = {79 and 0}

Thus, the whole numbers are 0 and 79.

8 0

2 years ago

Susan charges $8 per hour walking her neighbor’s dog. She charges $12 per hour babysitting. Part A: Define the variables. Part B

IgorC [24]

Answer:

Part A: The variables are the amount charged per hour dog walking and the amount charged per hour babysitting.

Part B: y=8d+12b

Step-by-step explanation:

4 0

2 years ago