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2 years ago

11

Ann, Emily, and Bob collect stickers. They have a total of 70 stickers in the ratio 2:3:5, respectively. How many stickers does

each child have?

2 answers:

kramer2 years ago

8 0

Answer:

The stickers are divided by groups of

2/10, 3/10 and 5/10

2/10 * 70 = 14

3/10 * 70 = 21

5/10 * 70 = 35

14 + 21 + 35 = 70

So, the stickers are allotted to the 3 children in a group of

14 to one child, 21 to another child, and 35 to the third child.

Step-by-step explanation:

Papessa [141]2 years ago

6 0

Answer:

The stickers are divided by groups of

2/10, 3/10 and 5/10

2/10 * 70 = 14

3/10 * 70 = 21

5/10 * 70 = 35

14 + 21 + 35 = 70

So, the stickers are allotted to the 3 children in a group of

14 to one child, 21 to another child, and 35 to the third child.

Step-by-step explanation:

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Answer:

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From the figure attached,

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By theorem,

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Therefore, DG ⊥ FG.

Option B will be the correct option.

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2 years ago

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2 years ago

Read 2 more answers

Approximately 80,000 marriages took place in the state of New York last year. Estimate the probability that for at least one of

sasho [114]

Answer:

a)0,45119

b)1

Step-by-step explanation:

For part A of the problem we must first find the probability that both people in the couple have the same birthday (April 30)

$P=\frac{1}{365} *\frac{1}{365}=\frac{1}{133225} \\$

Now the poisson approximation is used

λ=nP=80000*1/133225=0,6

Now, let X be the number of couples that birth April 30

P(X ≥ 1) =

1 − P(X = 0) =

$1-\frac{(e^-0.6)*(-0,6)^{0} }{0!}$

P(X ≥ 1) = 0,45119

B) Now want to find the

probability that both partners celebrated their birthday on th, assuming that the year is 52 weeks and therefore 52 thursday

$P=52*\frac{1}{365} *\frac{1}{365}=\frac{52}{133225} \\$

Now the poisson approximation is used

λ=nP=80000*52/133225=31.225

Now, let X be the number of couples that birth same day

P(X ≥ 1) =

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6 0

2 years ago

A manager wants to build 3-sigma x-bar control limits for a process. The target value for the mean of the process is 10 units, a

lubasha [3.4K]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Mean = 10

Sample size = 9

Standard deviation = 6

We need to find the upper and lower control limits.

so, Lower limit would be

$\bar{x}-3\dfrac{\sigma}{\sqrt{n}}\\\\=10-3\times \dfrac{6}{\sqrt{9}}\\\\=10-6\\\\=4$

Upper limit would be

$\bar{x}+3\dfrac{\sigma}{\sqrt{n}}\\\\=10+3\times \dfrac{6}{\sqrt{9}}\\\\=10+6\\\\=16$

Hence, Third option is correct.

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2 years ago