Answer:

Step-by-step explanation:
The given system is:


Since I prefer to use smaller numbers I'm going to divide both sides of the first equation by 3 and both sides of the equation equation by 6.
This gives me the system:


We could solve the first equation for
and replace the second
with that.
Let's do that.

Subtract
on both sides:

So we are replacing the second
in the second equation with
which gives us:





Now recall the first equation we arranged so that
was the subject. I'm referring to
.
We can now find
given that
using the equation
.
Let's do that.
with
:



So the solution is (8,-1).
We can check this point by plugging it into both equations.
If both equations render true for that point, then we have verify the solution.
Let's try it.
with
:


is a true equation so the "solution" looks promising still.
with
:


is also true so the solution has been verified since both equations render true for that point.
Keywords:
<em>Divide, polynomial, quotient, divisor, dividend, rest
</em>
For this case, we must find the quotient by dividing the polynomial
. We must build a quotient that, when multiplied by the divisor, eliminates the terms of the dividend until it reaches the rest, as shown in the attached figure. At the end of the division, to verify we must bear in mind that:

Answer:
See attached image
I believe Z=18
Example:
2/3z + 1 = 13
Multiply both sides: 2/3z * 3 + 1 * 3 = 13 * 3
Refine: 2/3z + 3 = 39
Subtract from both sides: 2z + 3 - 3 = 39 - 3
Refine: 2z=36
2z/2 = 36/12
Z=18
Answer:
? i dont think you finished the sentence
Step-by-step explanation: