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2 years ago

If t varies as v, and t = 2 4/7 when v = 13/14 , find v when t = 2 1/4.. v=. Direct variation. .

Mathematics

2 answers:

Ksivusya [100]2 years ago

7 0

Answer:

13/16

Step-by-step explanation:

"t varies as v" => t(v) = kv, where k is the constant of proportionality.

If t = kv, then this is true: 2 4/7 = k(13/14), or

18/7 = (13/14)k

Solving for k, we get:

(14/13)(18/7) = k = 36/13

Therefore, our equation is t = (36/13)v.

Now let t = 2 1/4 or 9/4, and find the corresponding v:

9/4 = (36/13)v, or v = (9/4)(13/36) = 0.8125 = 13/16

v = 13/16 when t = 2 1/4.

Alex_Xolod [135]2 years ago

6 0

Answer:

13/16

Step-by-step explanation:

Direct variation is when one variable is equal to a constant times another variable. In this case, t varies as v, so, t = k*v, where k is a constant. We know that t = 2 4/7 = 18/7 when v = 13/14, then:

18/7 = k*13/14

18/7*(14/13) = k

36/13 = k

Replacing in the formula with t = 2 1/4 = 9/4, we get:

9/4 = 36/13*v

9/4*(13/36) = v

13/16 = v

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Answer: Jack can fill his feeder 12 times with 4 pounds of birdseed.

Step-by-step explanation:

You need to analize the information given in the exercise, You know that every time Jack fills the feeder, he put $\frac{1}{3}$ pounds into it.

Then, in order to solve this exercise, let "x" represents the number of times that Jack can fill his feeder with 4 pounds of birdseed.

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2 years ago

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alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed. These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

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"landing on an unshaded portion and landing on a number less than 2 "

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GalinKa [24]

Answer:

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2 years ago

The commute time to work in the U.S. Has a bell shaped distribution with a population mean of 24.4 minutes and a population stan

Schach [20]

Answer:

Q1 a) 0.9545

b) 0.02275

c) 0.97725

Q2 z is approximately equal to -1.466

Step-by-step explanation:

Q1 The given information are;

The mean time to commute to work = 24.4 minutes

The standard deviation = 6.5 minutes

a) The z-score for 11.4 is given as follows;

$Z=\dfrac{x-\mu }{\sigma }$

Where;

x = Observed value 11.4

μ = The mean = 24.4 minutes

σ = The standard deviation = 6.5 minutes

$Z=\dfrac{11.4-24.4 }{6.5 } = -2$

The z-score for 37.4 is given as follows;

$Z=\dfrac{37.4-24.4 }{6.5 } = 2$

-2 < z < 2, which gives, from the z-score table;

The probability of commute time to be between 11.4 minutes and 37.4 minutes = 0.97725 - 0.02275 = 0.9545

b) From the z-score table, the probability that the commute time to be less than 11.4 minutes = The probability at z = -2 = 0.02275

c) From the z-score table, the probability that the commute time to be greater than 37.4 minutes = The probability at z = 2 = 0.97725

Q2 The the z-score that corresponds to a commute time of 15 minutes is given as follows;

$Z=\dfrac{x-\mu }{\sigma }$

$Z=\dfrac{15-24.4 }{6.5 } = -\dfrac{94}{65} \approx -1.466$

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2 years ago