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arlik [135]
2 years ago
5

Sasha runs at a constant speed of 3.8 meters per second for 1/2 hour.Then she walks at a constant rate of 1.5 meters per second

for 1/2 hour.How far did Sasha run and walk in 60 minutes?
Mathematics
1 answer:
Arisa [49]2 years ago
3 0

Answer:

Step-by-step explanation:

Distance covered = speed × time.

Sasha runs at a constant speed of 3.8 meters per second for 1/2 hour.

This means distance covered while running would be

3.8 × 1/2 = 1.9 meters

Then she walks at a constant rate of 1.5 meters per second for 1/2 hour. This means distance covered while walking would be

1.5 × 1/2 = 0.75 meters

Total distance that Sasha covered while running and walking in 60 minutes would be

1.9 + 0.75 = 2.65 meters

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There are 5 x 10 = 50 different outcomes.

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Then 50 - 9 =  41 are the possibilities that the product of the two numbers is less than 30.

The probalility, then, is 41/50 = 0.82
7 0
2 years ago
Read 2 more answers
Algebra There were 4 times the number of students in fourth grade at the basketball game.How many students attended the basketba
denis-greek [22]

Answer:

200 students attended the basketball game

Step-by-step explanation:

The complete question in the attached figure

Let

x ------> the number of students in fourth grade

s -----> the number of students at the basketball game

we know that

The number of students at the basketball game is four times the number of students in fourth grade

so

The linear expression is

s=4x -----> equation A

x=50\ students\ in\ fourth\ grade -----> equation B

substitute equation B in equation A and solve for y

s=4(50)

s=200\ students\ at\ the\ basketball\ game

therefore

200 students attended the basketball game

8 0
2 years ago
3) Last year Kerry’s take home pay was £15 000 She spent 40% of her take home pay on rent. She used the rest of her take home pa
gregori [183]
3,000. You take 15,000 and multiply by .4 to get how much she spent on rent (6,000). They you subtract the rent money from her total pay to get her money that she spent on living expenses, clothes and entertainment in total (9,000). Since she spent her money in six parts (3+2+1), you divide 9,000 by 6 to get 1,500 to get each part. Since for entertainment she has two parts you multiply 1,500 by 2 to get 3,000.
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2 years ago
Part A: Maci made $170 grooming dogs one day with her mobile dog grooming business. She charges $60 per appointment and earned $
Anastaziya [24]

Answer:

A. 60a + 50 = 170

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C. Part B had to pay a rental fee of $10 per appointment

Hope this helps:)

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8 0
1 year ago
A village was founded four hundred years ago by a group of 20 people. In this village, the population triples every one hundred
Paha777 [63]

Answer:

Step-by-step explanation:

Treat this like compound interest:  Use A = P(1 + r)^t.

Here, P is the initial population and A is 3 times that, or 3P.  Since P = 20 people, 3P = 60 people,

and this population is reached after 100 years.

We need to determine r, substitute its value into the formula A = P(1 + r)^t, and then determine the population of the village after 400 years.

60 = 20(1 + r)^100

Simplifying, 3 = (1 + r)^100.

Taking the natural log of both sides,

ln 3 = 100 ln (1 + r), or

                   ln 3

ln (1 + r) = ---------------

                    100

              = 1.0986 / 100 = 0.01986

We must solve this for r.  Raising e to the power ln (1 + r), on the left side of an equation, and raising e to the power 0. 01986 on the right side, we get:

1 + r = 3, so r must = 2.

Now find the pop of the village today.  Use the same equation:  A = P (1+r)^t.

A = 20(1 +2)^4 (hundreds),

or

A = 20(3)^4, or

A = 81

The population after 400 years is 81.

8 0
2 years ago
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