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AysviL [449]
2 years ago
12

I just purchased 9 products from you at $44.00. I just realized my company offers a 20% discount on all of your products. Can yo

u tell me what my new total should be?
Mathematics
2 answers:
sleet_krkn [62]2 years ago
8 0
44 × 20% = 8.8

44 - 8.80 = 35.2

Your new total should be 35.20.

Hope that helped! c:
mamaluj [8]2 years ago
4 0
So the new total is:
9 * (44*.8) since the 20% discount means you only pay 80% of the original $44 per item
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How do i find each product by factoring the tens? 3x2, 3x20, and 3x200
RUDIKE [14]
Well, since it only asking about the product, you don't have to multiply the result 
The product would be :
3 x 2 = 6
3x 20 =  3 x 2 x 10  = 60
3 x 200 = 3 x 2 x 10 x 10 = 600

hope this helps
6 0
2 years ago
Read 2 more answers
Which term in the arithmetic sequence 11, 4,-3 . . . is -129?​
telo118 [61]

Answer:

23rd term

Step-by-step explanation:

Plz mark as Brainliest!

4 0
2 years ago
The store sells a 9 ounce jar of mustard for $1.53 and a 15 ounce for $2.55 explain whether the cost of the mustards have the sa
astraxan [27]

Answer:

same amount of money

Step-by-step explanation:

3 0
2 years ago
The square of a number decreased by 3 times the number 28 find all possible values for the number
stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number  

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

a^2 - 3a = 28

a^2 - 3a - 28 = 0

Let us solve the above quadratic equation

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28

\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}

Thus the possible values of number are 7 and -4

5 0
2 years ago
Given the values of the linear functions f (x) and g(x) in the tables, where is (f – g)(x) positive?
alexandr402 [8]

Comparing the functions, from the tables, it is found that (f - g)(x) is positive in the interval (–∞, 9) .

----------------------

  • For the subtraction function, we simply subtract both functions, thus:

(f - g)(x) = f(x) - g(x)

  • It is positive if f is greater than g, that is: f(x) > g(x).
  • It is a linear function, so one function is greater before the equality, one after.
  • They are equal at x = 9.
  • If x < 9, f(x) > g(x), and thus, (f - g)(x) is positive, which means that the desired interval is:

(–∞, 9)

A similar problem is given at brainly.com/question/24610273

4 0
1 year ago
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