Answer: the boy won 10 games
Step-by-step explanation:
Let's call B as the number of games won by the boy, and F as the number of games won by the father.
We know that, there is a total of 26 games:
B + F = 26.
We know that in each game won by the boy, he wins 8 cents, for every game that the father wins, the boy losses 5 cents, and we know that at the end of the 26 games, the boy did not win or lose any money, so we have:
B*8 + F*(-5) = 0.
Then we have a system of equations:
B + F = 26
8*B - 5*F = 0.
The first step is isolating one of the variables. Let's start isolating F in the first equation:
B + F = 26
F = 26 - B.
Now we can replace this in the second equation:
8*B - 5*F = 0
8*B - 5*(26 - B) = 0
8*B + 5*B - 5*26 = 0
13*B = 5*26
B = 5*26/13 = 5*2 = 10
So the boy won 10 games (then the father won the other 16 games)
We have been given an equation
. We are asked to solve the equation for t.
First of all, we will divide both sides of equation by a.


Now we will take natural log on both sides.

Using natural log property
, we will get:

We know that
, so we will get:


Now we will divide both sides by c as:


Therefore, our solution would be
.
<u>ANSWER:</u>
Kari bought 3 boxes of cookies to share. The algebraic expression is 
<u>Solution:</u>
Given, Kari bought 3 boxes of cookies to share with a book club.
Each box contains 12 cookies.
So, in total we have 3 x 12 cookies = 36 cookies.
Now, we have to find how many cookies can each person p will get.
Let, the total number of persons be x.
Then, after equally sharing the cookies,


Hence, the algebraic expression is 
The probability that a child with a speaking part is chosen randomly would be 2:5.