Monthly payments, P = {R/12*A}/{1- (1+R/12)^-12n}
Where R = APR = 4.4% = 0.044, A = Amount borrowed = $60,000, n = Time the loan will be repaid
For 20 years, n = 20 years
P1 = {0.044/12*60000}/{1- (1+0.044/12)^-12*20} = $376.36
Total amount to be paid in 20 years, A1 = 376.36*20*12 = $90,326.30
For 3 years early, n = 17 year
P2 = {0.044/12*60,000}/{1-(1+0.044/12)^-12*17} = $418.22
Total amount to be paid in 17 years, A2 = 418.22*17*12 = $85,316.98
The saving when the loan is paid off 3 year early = A1-A2 = 90,326.30 - 85,316.98 = $5,009.32
Therefore, the approximate amount of savings is A. $4,516.32. This value is lower than the one calculated since the time of repaying the loan does not change. After 17 years, the borrower only clears the remaining amount of the principle amount.
<u>Answer:</u>
<u>As the number of copies increases The dimension of images continues to decrease until reaching 0. </u>
<u>Step-by-step explanation:</u>
Remember, that the term dimension refers not to an unlimited/unending length but to a specific measurable length.
Therefore, as both copy machines reduces the dimensions of images that are run through the machines over time the dimensions of images would decrease until reaching 0; Implying that the dimension is so small to be invisible, in a sense becoming 0.
168/3 = 56
<em>Therefore, Chad is driving the car in 56 mph.</em>
672/56 = 12
<em>Therefore, Chad drives 672 miles in 12 hours.</em>
308/11 = 28
<em>Therefore, Chad drives 28 miles per gallon of gas.</em>
672/28 = 24
<em>Therefore, Chad uses 24 gallons of gas to drive 672 miles.</em>
Least to greatest, the triples are (2x, x²-1, x²+1). Thus the value in the first column of the table is half the value of the first of the triples. Your completed table will be
