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2 years ago

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Chad drove 168 miles in 3 hours. How many miles per hour did chad drive? Chad will drive 672 more miles. He continues to drive a

t the same rate. How many hours will it take chad to drive the 672 miles? Chad stopped and filled the car with 11 gallons of gas. He had driven 308 miles using the previous 11 gallons of gas. How many miles per gallon did chad cars get? Chad's car continues to get the same number of miles per gallon. How many gallons of gas will chads car use to travel 672 miles?

1 answer:

larisa86 [58]2 years ago

3 0

168/3 = 56

<em>Therefore, Chad is driving the car in 56 mph.</em>

672/56 = 12

<em>Therefore, Chad drives 672 miles in 12 hours.</em>

308/11 = 28

<em>Therefore, Chad drives 28 miles per gallon of gas.</em>

672/28 = 24

<em>Therefore, Chad uses 24 gallons of gas to drive 672 miles.</em>

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What you must do in this case is to use the potential type function given in the problem:
a (b) ^ x = c
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Answer:
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Answer:

<em>c=6, d=2</em>

Step-by-step explanation:

<em>Equations </em>

We must find the values of c and d that make the below equation be true

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Let's cube both sides of the equation:

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The left side just simplifies the cubic root with the cube:

$162x^cy^5=\left (3x^2y \sqrt[3]{6y^d}\right)^3$

On the right side, we'll simplify the cubic root where possible and power what's outside of the root:

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Simplifying

$x^cy^5=x^6y^{3+d}$

Equating the powers of x and y separately we find

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<u>Step-by-step explanation:</u>

Step 1 :Finding length of XY

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here

$x_1$ = 5

$x_2$ =3

$y_1$ = -1

$y_2$ =2

XY = $\sqrt{(3-5)^2 +(2 -(-1))^2}$

XY = $\sqrt{(3-5)^2 +(2 +1))^2}$

XY = $\sqrt{(-2)^2 +(3))^2}$

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Step 2 :Finding length of YZ

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$x_1$ = 3

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YZ = $\sqrt{(5-3)^2 +(5-2)^2}$

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Step 3 : :Finding length of ZW

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here

$x_1$ = 5

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ZW = $\sqrt{4 +9}$

ZW = $\sqrt{(13)}$

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here

$x_1$ = 7

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