What is the 12th term of the sequence

Round 96.9617186007 to the nearest tenth.

Pavlova-9 [17]

if you're talking about the whole number, 100.96. if you're referring to decimal place values; 96.70.

underline the digit that you round to

circle the digit to the right

five or more goes up

four or less stays the same

everything behind becomes a zero.

6 0

2 years ago

Read 2 more answers

Triangle J K L is shown. Angle K J L is 58 degrees and angle J L K is 38 degrees. The length of J K is 2.3 and the length of J L

Romashka-Z-Leto [24]

Try 3.7 and see it u got it

5 0

2 years ago

Read 2 more answers

Employees in the marketing department of a large regional restaurant chain are researching the amount of money that households i

kap26 [50]

Answer:

The z-score for the group "25 to 34" is 0.37 and the z-score for the group "45 to 54" is 0.25.

Step-by-step explanation:

The data provided is as follows:

25 to 34 45 to 54

1329 2268

1906 1965

2426 1149

1826 1591

1239 1682

1514 1851

1937 1367

1454 2158

Compute the mean and standard deviation for the group "25 to 34" as follows:

$\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [1329+1906+...+1454]=\frac{13631}{8}=1703.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1086710.875}=394.01$

Compute the z-score for the group "25 to 34" as follows:

$z=\frac{x-\bar x}{s}=\frac{1851-1703.875}{394.01}=0.3734\approx 0.37$

Compute the mean and standard deviation for the group "45 to 54" as follows:

$\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [2268+1965+...+2158]=\frac{14031}{8}=1753.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1028888.875}=383.39$

Compute the z-score for the group "45 to 54" as follows:

$z=\frac{x-\bar x}{s}=\frac{1851-1753.875}{383.39}=0.25333\approx 0.25$

Thus, the z-score for the group "25 to 34" is 0.37 and the z-score for the group "45 to 54" is 0.25.

8 0

2 years ago

Given: FGKL is a trapezoid, m∠F=90°, m∠K=120°, FK=LK=a Find: The length of midsegment.

noname [10]

Answer:

(3/4)a

Step-by-step explanation:

The angle at K is 120°, so the angle at L is its supplement: 60°. That makes triangle FKL an equilateral triangle with a base of FL = a. The vertex at K is centered over the base, so is a/2 from G.

The midsegement length is the average of GK and FL, so is ...

midsegment = (GK +FL)/2 = (a/2 +a)/2

midsegment = (3/4)a

8 0

1 year ago

Computer upgrades have a nominal time of 80 minutes. samples of five observations each have been taken, and the results are as l

Goshia [24]

The answer:
the upper and lower control limits (uclim and lclim) for mean formula is

for the mean chart
uclim= x+A2xR
where x = sum(of the value) / number of each value
and for
lclim=x+A2xR

R is the range such that R= Xmax - Xmin

in the case of the sample 1: S1
the data are:
79.2 78.8 80.0 78.4 81.0

the mean is x1 = (79.2 + 78.8 + 80.0 + 78.4 + 81.0) / 5= 79.48
its range is R 1= 81.0 -78.4 = 2.6

we can do the same method for finding the mean chart and range for all samples
S2: x2= 80.14 , R2=2.3
S3: x3= 80.14 , R3=1.2
S4: x4= 79.60 , R4=1.7
S5: x5= 80.02 , R5=2.0
S6: x6=80.38 , R6=1.4

therefore the average value is X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95 and lclim is always equal to 0, because D3=0

we can say that the process is not in control.

3 0

2 years ago