Answer:
B. 96
Step-by-step explanation:
Let x represent score of final third exam.
We have been given that in a given course a student receives preliminary examination grades of 81, 85, and 95.
Let us find average of preliminary scores.

We have been given that the final examination is weighed for one-third and the average of the preliminary grades is weighed as 2/3 of the final grade. This means that final grade is equally weighed into 3 parts. The two parts are 87 each and third part is x.
Using our given information, we can set an equation as:






Therefore, the final examination grade should be 96 for a semester average of 90.
Answer:addition and multiplication
Step-by-step explanation:
I just did it
Answer:
989000
Step-by-step explanation:
Divide 2,967 ÷ 0.003
The perimeter is the sum of the enclosing side.
From the figure, the perimeter is
P = 11 + (x-2) + (11-3) + [(x-2) - (x-11)] + (x-11)
= 11 + x - 2 + 8 + 9 + x - 11
= 2x + 15
Answer: 2x + 15
So to find the avrage u r going to add all the numbers then divide by the nuber of nubers u have there that will give u ur answer