Which point shows the location of 5 – 2i on the complex plane below? On a coordinate plane, points A, B, C, and D are shown. Poi
nt A is 2 units to the left of the origin and 5 points up from the origin. Point B is 2 points to the right of the origin and 5 points down from the origin. Point C is 5 points to the right of the origin and 2 points down from the origin. Point D is 5 points to the left of the origin and 2 points down from the origin. point A point B point C point D
2 answers:
Answer:
The Point C shows the location of 5-2i in the complex plane: 5 points to the right of the origin and 2 points down from the origin.
Step-by-step explanation:
We have the complex number 5-2i and we have to show the location of the point that represents that number in the complex plane
In the complex plane the real numbers are located in the horizontal axis, increasing to the right. The positives real numbers are at the right of the origin and the negatives to the left.
The complex numbers are located in the vertical axis, with the positives over the origin and the negatives below the origin.
This complex number 5-2i is the sum of a real part (5) and a imaginary part (-2i), so the point will be 5 units rigth on the horizontal axis (for the real part) and 2 units down in the vertical axis (for the imaginary part).
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Check the picture below.
so notice, their perimeter is the same, because the perimeter is just one rod anyway, and all rods are the same length, thus
so notice, their perimeter is the same, because the perimeter is just one rod anyway, and all rods are the same length, thus
Answer:
The constant term in the function is 5
Step-by-step explanation:
we have
where
b is the y-intercept or the constant term of the function
Remember that
The x-intercept is the value of x when the value of the function is equal to zero
so
For x=-3 ----> f(x)=0
For x=-5 ----> f(x)=0
substitute any of the intercepts in the function
For x=-3
Verify with the other intercept
For x=-5
---> is true
therefore
The constant term in the function is 5