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Vladimir [108]
2 years ago
14

Read the ruler in millimeters to the correct degree of precision (The ruler is in between the halfmark and the sixth mark on the

ruler between 3 and 4) ​
Mathematics
1 answer:
Vitek1552 [10]2 years ago
6 0

Answer:

3 1/2

Step-by-step explanation:

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Evaluate these quantities.<br> a.−17 mod 2<br> b.144 mod 7<br> c.−101 mod 13<br> d.199 mod 19
Eduardwww [97]
Modular arithmetic is used to find the remainder when dividing the first number by the second number you can divide the term then multiply the  (or use the mod function of a graphing calculator with the first term first in the ordered pair and the second in the second term.

-17/2 = 8.5   2*.5 =1
a. 1
-144/7 = -20 5/7 . 4/7 *7 = 4
b. 4
-101/13 =
c. 3
199/19=
d.9

6 0
1 year ago
Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot
Anastasy [175]

Option B : \frac{1}{\sqrt[3]{x^{5} } } is the expression equivalent to x^{-\frac{5}{3}

Explanation:

The given expression is x^{-\frac{5}{3}

Rewriting the expression x^{-\frac{5}{3} using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

\frac{1}{x^{\frac{5}{3} } }

Simplifying, we get,

\frac{1}{\left(x^{5}\right)^{\frac{1}{3}}}

Applying the rule, a^{\frac{1}{n}}=\sqrt[n]{a}

Thus, we have,

\frac{1}{\sqrt[3]{x^{5} } }

Now, we shall determine from the options that which expression is equivalent to x^{-\frac{5}{3}

Option A: \frac{1}{\sqrt[5]{x^{3} } }

The expression \frac{1}{\sqrt[5]{x^{3} } } is not equivalent to simplified expression  \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression \frac{1}{\sqrt[5]{x^{3} } } is not equivalent to x^{-\frac{5}{3}

Hence, Option A is not the correct answer.

Option B: \frac{1}{\sqrt[3]{x^{5} } }

The expression \frac{1}{\sqrt[3]{x^{5} } } is equivalent to the simplified expression  \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression \frac{1}{\sqrt[3]{x^{5} } } is equivalent to x^{-\frac{5}{3}

Hence, Option B is the correct answer.

Option C: -\sqrt[3]{x^5}

The expression -\sqrt[3]{x^5} is not equivalent to the simplified expression \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression -\sqrt[3]{x^5} is not equivalent to x^{-\frac{5}{3}

Hence, Option C is not the correct answer.

Option D: -\sqrt[5]{x^3}

The expression -\sqrt[5]{x^3} is not equivalent to the simplified expression \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression -\sqrt[5]{x^3} is not equivalent to x^{-\frac{5}{3}

Hence, Option D is not the correct answer.

4 0
1 year ago
Read 2 more answers
What is the angle θ that the field e⃗ makes with the surface of the slab, which is perpendicular to the x direction? express you
Virty [35]
The angle θ that the field e⃗ makes with the surface of the slab, which is perpendicular to the x direction is <span>θ = -1.57 <span>rad


Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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6 0
1 year ago
Read 2 more answers
which function increases at a faster rate on 0 to infinity, f(x) = x2 or g(x) = 2x? explain your reasoning
Tcecarenko [31]
F(x) = x²    increases at a faster rate than g(x) = 2x.

f(x)

Reason:

x =  0,   1,   2,   3,   4,   5,   6,   7

f(x) = 0,   1,  4,  9,   16,  25,   36,   49

g(x) = 0,  2,  4,   6,    8,  10,    12,    14.

Comparing the values of f(x) and g(x), we can see that that of f(x) are far higher than that of g(x) for the same values of x.

So f(x) increases at a faster rate. 
7 0
1 year ago
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A surveyor, Toby, measures the distance between two landmarks and the point where he stands. He also measured the angles between
Tju [1.3M]

The Set Up:

x² = (Side1)² + (Side2)² - 2[(Side1)(Side2)]

Solution:

cos(Toby's Angle) • x² = 55² + 65² - 2[(55)(65)] cos(110°)

x² = 3025 + 4225 -7150[cos(110°)]

x² = 7250 - 2445.44x =

√4804.56x = 69.31m

The distance, x, between two landmarks is 69.31m.

Note: The answer choices given are incorrect.

3 0
1 year ago
Read 2 more answers
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