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bazaltina [42]
2 years ago
8

At the beginning of the game, April had a score of −140 points. April played for another 20 minutes, and her final score was −27

5.
Mathematics
1 answer:
alexgriva [62]2 years ago
8 0
And what are we working out...??
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The function y = square root sign x is translated using the rule (x, y) → (x – 7, y + 2)to create f(x). What is the domain of f(
Mama L [17]

Answer:

Second option {x | x > 7}

Step-by-step explanation:

We have the function

y = \sqrt{x}

We know that the square root of a negative number has no solution in the real ones. Therefore the domain of this function is x > 0

When applying the transformation:

(x, y) \to (x - 7, y + 2) we have a translation of the original function in 7 units to the right and 2 units to the top:

f(x) = \sqrt{x-7} + 2

In the same way we must guarantee that (x-7)> 0

Then x > 7.

Therefore the domain of f(x) is {x | x > 7}

7 0
2 years ago
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The scores of the students on a standardized test are normally distributed, with a mean of 500 and a standard deviation of 110.
ololo11 [35]
Μ = 500, population mean
σ = 110, population stadard deviation

The given table is
z  0.00       0.25       0.35      0.45      1.00      1.26       1.35     1.36
P  0.5000  0.5987  0.6368  0.6736  0.8413  0.8961  0.9115  0.9131

Range of random variable is X = [350, 550].

Calculate z-score for x = 350.
z = (350 - 500)/110 = -1.364
From the given tables,
The probability at x = 350 is
1 - 9131 = 0.0869

Calculate the z-score for x = 550.
z = (550 - 500)/110 = 0.454
From the given tables,
The probability at x = 550 is 0.6736

The probability that x =[350,550] is 
0.6736 - 0.0869 = 0.5867

Answer:  0.5867  (or 58.7%)

4 0
2 years ago
Read 2 more answers
Explain how employee benefits affect total employment compensation
dlinn [17]
Employee benefits are generally considered added compensation in addition to wages or salary.  so if it were represented as a function it would be C=b+w. The total compensation C would be equal to benefits b plus wages or salary w.
8 0
2 years ago
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Statistics In the manual “How to Have a Number One the Easy Way,” it is stated that a song “must be no longer than three minutes
dimaraw [331]

Answer:

We conclude that the sample is from a population of songs with a mean greater than 210 seconds.

Step-by-step explanation:

We are given that a simple random sample of 40 current hit songs results in a mean length of 252.5 seconds.

Assume that the standard deviation of song lengths is 54.5 sec.

Let \mu = <u><em>population mean length of the songs</em></u>

So, Null Hypothesis, H_0 : \mu \leq 210 seconds      {means that the sample is from a population of songs with a mean smaller than or equal to 210 seconds}

Alternate Hypothesis, H_A : \mu > 210 seconds      {means that the sample is from a population of songs with a mean greater than 210 seconds}

The test statistics that will be used here is <u>One-sample z-test statistics </u>because we know about population standard deviation;

                              T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of songs = 252.5 seconds

            \sigma = population standard deviation = 54.5 seconds

            n = sample of current hit songs = 40

So, <u><em>the test statistics</em></u> =  \frac{252.5-210}{\frac{54.5}{\sqrt{40} } }

                                   =  4.932

The value of z-test statistics is 4.932.

Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 4.932 > 1.645, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the sample is from a population of songs with a mean greater than 210 seconds.

4 0
2 years ago
What is the quotient of StartStartFraction 90 (cosine (StartFraction pi Over 4 EndFraction) + I sine (StartFraction pi Over 4 En
Gelneren [198K]

Answer:

The answer is C

Step-by-step explanation:

8 0
2 years ago
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