What is the value of x in the equation 8x – 2y = 48, when y = 4?

Mathematics

1 answer:

luda_lava [24]1 year ago

8 0

Answer:

Step-by-step explanation:

8x-2y=48, replace y with 4, 8x-2(4)=48, multiply, 8x-8=48, add 8 to both sides to remove the -8, 8x=56 and finally divide by 8 to remove 8 from x, x=7.

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Hello,

I am going to remember:

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