A bag contains 7 red discs, 5 green discs and 2 pink discs.
1 answer:
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Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer: (1.5, 0)
Step-by-step explanation:
Given : The shape of his satellite can be modeled by where x and y are modeled in inches.
Now,the given equation is a equation of parabola.
Here, coefficient of x is positive, hence the parabola opens rightwards.
On comparing this equation with standard equation , we get
In standard equation, coordinates of focus=(m,0)
Thus for given equation coordinates of focus=(1.5,0)