Hey there!
Each step is three feet. This can be represented by 3s= feet. We can plug that in to figure out our side lengths.
20(3)=60
40(3)=120
Now we can multiply these two together to get the area.
120(60)= 7,200
Therefore, his backyard is about 7,200 square feet.
I hope this helps!
Answer:
(5.4k+7.9m+8.1n) centimeters
Step-by-step explanation:
Given the side length of a triangle;
S1 = (1.3k+3.5m) cm
S2 = (4.1k-1.6n) cm
S3 = (9.7n+4.4m) cm
Perimeter of the triangle = S1+S2 + S3
Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)
Collect the like terms;
Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n
Perimeter of the triangle = 5.4k+7.9m+8.1n
Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters
As given,
Loan amount is = $45000
Rate of interest = 8.5%
So, Tony's mortgage will attract an interest of:
= $3825 (this is yearly)
And for 1st month it will be =
= $318.75
As given, the first month's payment is $390.60 and this covers the interest Additional amount ($390.60 - $318.75 = $71.85) is a payment against the principle.
Hence, the new principle after the 1st month is $71.85 less than $45000
= 45000-71.85 = $44928.15
Hence, the last option $44928.15 is the correct answer.
The fencing line x is the height of a rectangle triangle of base = y, hypothenuse of 9 m, so we use Pythagoras theorem to solve:
hyp^2 = height^2 + base^2
9^2 = x^2 + y^2
x^2 = 81 - y^2
we can see that x is also the height of another rectangle triangle of base = 15 - y, hypothenuse of 12 m, so we use Pythagoras theorem to solve:
hyp^2 = height^2 + base^2
12^2 = x^2 + (15 - y)^2
lets expand:
144 = x^2 + 225 - 30y + y^2
substitute x^2 from the first equation in the last:
144 = 81 - y^2 + 225 - 30y + y^2
144 = 81 + 225 - 30y
30y = -144 + 81 + 225
y = 5.4 m
substitute in the fence equation:
x^2 = 81 - y^2
x^2 = 81 - 5.4^2
x = 7.2 m that is the length of the fence
The domain would be x ≥ 0.
This is because the outlet cannot have profit before it was open. Therefore, the growth must be from year 0 to present. If they give a year as starting, you can have an upper limit too, but there is not enough information here to determine that information.