To find the percentage of a number out of another number you just divide.
64 is 200% of 32 because 64/32 is 2.
The answer is:

But if x2 was supposed to be x^2 then the answer is:
Answer:Perry and Lorna take the maximum time and Maria and Lorna take the minimum time when they work together.
Explanation: Since, according to the question- Perry takes time when he works alone = 3 hours
Similarly, Maria takes = 2 hours, While Lorna takes= 2 hours 30 minutes or 2.5 hours.
since, there are three people thus their are three possibility to choose any two of them.
1- when Perry and Maria work together then time taken by them is
=
= 6/5= 1 hour 12 minutes.
2- when Maria and Lorna work together then time taken by them is
= 10/9= 1 hours 1/9 minutes ≈ 1 hours 7 min
3- when Perry and Lorna work together then time taken=
= 15/11= 1 hour 4/11 minutes≈ 1 hours 21 minutes
From the above explanation, it has been proved that when we talk about 2 members team then Perry and Lorna take the maximum time. While Maria and Lorna take the minimum time when they work together.
Answer: For

Nick does not has enough money to follow this recommendation.
Step-by-step explanation:
Given: A self-service car wash charges $4 for the initial 5 minutes plus an additional $0.75 for each minute after that.
Let y be the cost for car wash for m minutes then
such that at m= 5 , y=4 which is the cost for car wash (dollars) for first 5 minutes.
Also, A car enthusiast magazine recommends spending at least 15 minutes to properly wash a car.
For

But Nick has $10 which is less than $11.5, so he does not has enough money to follow this recommendation.
Answer:
A) ∃y(¬P(y))
B) ∀y(P(y) ^ Q(y))
C) ∀y(P(y) ^ Q(y))
D) ¬∃y(P(y) ^ Q(y))
E) ∃y(¬P(y) ^ Q(y))
Step-by-step explanation:
We will use the following symbols to answer the question;
∀ means for all
∃ means there exists
¬ means "not"
^ means "and"
A) Something(y) is not in the correct place is represented by;
∃y(¬P(y))
B) For All tools are in the correct place and are in excellent condition, let all tools in the correct place be P(y) and let all tools in excellent condition be Q(y).
Thus, we have;
∀y(P(y) ^ Q(y))
C) Similar to B above;
∀y(P(y) ^ Q(y))
D) For Nothing is in the correct place and is in excellent condition:
It can be expressed as;
¬∃y(P(y) ^ Q(y))
E) For One of your tools is not in the correct place, but it is in excellent condition:
It can be expressed as;
∃y(¬P(y) ^ Q(y))