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almond37 [142]
2 years ago
15

Perry, maria, and lorna are painting rooms in a college dormitory. working alone, perry can paint a standard room in 3 hours, ma

ria can paint a standard room in 2 hours, and lorna can paint a standard room in 2 hours 30 minutes. perry, maria, and lorna have decided that, to speed up the work, 2 of them will paint a standard room together. select the value closest to the shortest time in which a 2-person team could paint a standard room, and select the value closest to the longest time in which a 2-person team could paint a standard room, with each person working at his or her respective rate. make only two selections, one in each column.
Mathematics
2 answers:
RUDIKE [14]2 years ago
7 0
We know that
<span>1) perry can paint a standard room in 3 hours
so
100% of the room--------------> 3 hours
x%-----------------> 1 hour
x=100/3-----< x=33.33%

2) </span>maria can paint a standard room in 2 hours
so
100% of the room--------------> 2 hours
x%-----------------> 1 hour
x=100/2-----< x=50%

3) lorna can paint a standard room in 2.5 hours
so
100% of the room--------------> 2.5 hours
x%-----------------> 1 hour
x=100/2.5-----< x=40 %

therefore
perry can paint 33.33% of a standard room in 1 hour
maria can paint 50 % of a standard room in 1 hour
lorna can paint 40 % of a standard room in 1 hour


Part a) Find <span>the value closest to the shortest time in which a 2-person team could paint a standard room
</span>the value closest to the shortest time is which maria and lorna
<span>
team (maria +lorna) =(50%+40%)---------> 90%  in 1 hour
so
90%------> 1 hour
100%-----> x
x+100/90-----> x=1.11 hours-----> 1 h 7 min

Part b) </span>Find the value closest to the longest time in which a 2-person team could paint a standard room
the value closest to the longest time is which perry and lorna<span>

</span>team (perry+lorna) =(33.33%+40%)---------> 73.33%  in 1 hour
so
73.33%------> 1 hour
100%-----> x
x+100/73.33-----> x=1.36 hours-------> 1 h 22 min

Leviafan [203]2 years ago
3 0

Answer:Perry and Lorna take the maximum time and Maria and Lorna take the minimum time when they work together.

Explanation: Since, according to the question- Perry takes time when he works alone = 3 hours

Similarly, Maria takes = 2 hours, While Lorna takes= 2 hours 30 minutes or 2.5 hours.

since, there are three people thus their are three possibility to choose any two of them.

1- when Perry and Maria work together then time taken by them is \frac{1}{1/2+1/3}=\frac{1}{5/6}= 6/5= 1 hour 12 minutes.

2- when Maria and Lorna work together then time taken by them is \frac{1}{1/2 + 1/2.5}= 10/9= 1 hours 1/9 minutes ≈ 1 hours 7 min

3- when Perry and Lorna work together then time taken= \frac{1}{1/3+1/2.5}= 15/11= 1 hour 4/11 minutes≈ 1 hours 21 minutes

From the above explanation, it has been proved that when we talk about 2 members team then Perry and Lorna take the maximum time. While Maria and Lorna take the minimum time when they work together.


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HELP!!!!
Nonamiya [84]
Your answer is E. $25.

First let under 12 = u, over 12 = o, and adults = a.
We can now write the equations:

2u + 3a + 3o = 174
4u + 2a = 122
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Because we know that a + o = 46, and 3a + 3o is in the first equation, we can multiply 46 by 3 to get what 3a + 3o equals. This makes 138.
Now we can substitute 138 into the first equation to get 2u + 138 = 174
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u = 18

Now that we know what u equals, we can substitute it in to the second equation to get:
4(18) + 2a = 122
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a = $25

I hope this helps! Let me know if you have any questions :)
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