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2 years ago

what do i write for this " Write a problem that requires adding 1 to the quotient when interpreting the remainder."

1 answer:

6 0

You should write a ( real world situation ) question that can only have whole numbers as a solution because you would divide and then you can not have a fraction left over so instead you add one. For instance there are 132 students going on a field trip. 20 students can fit on each bus. how many buses are needed? 7 because when you divide 132 by 20 you get 6 remainder 12. You can not just make 12 students walk to the location so you would add an extra bus.

You might be interested in

An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)

erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

18-20 Not 18-20 Total

Male 0.23 0.35 0.58

Female 0.16 0.26 0.42

Total 0.39 0.61 1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) = 0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0

2 years ago

Laurissa rolls two number cubes, each with the numbers 1 through 6. Laurissa adds the numbers that appear in the roll. Which two

defon

Answer:

Let's analyze the possible sums of both dices, i will use the notation:

Dice1 + Dice 2 = sum.

also remember that we have 2 dices, with 6 options each.

So the total number of combinations is 6*6 = 36

we have 36 possible outcomes.

I will start at the extremes, the minimum that we can sum is 2, and the maximum is 12, then:

We can have 2 if:

1 + 1 = 2

only one permutation.

and 12 if:

6 + 6 = 12

Again, only one permutation.

so 2 and 12 have the same chance (1 out of 36)

now, to have 3 we can have:

2 + 1 = 3

1 + 2 = 3.

and to have 11

5 + 6 = 11

6 + 5 = 11

Again, 3 and 11 have the same probability (2 out of 36 options)

And now we can see a pattern.

4 and 10 will have the same chance.

5 and 9 will have the same chance

6 and 8 will have the same chance

7 is the only number that has an unique chance (and it has the largest one)

3 0

2 years ago

There are 200 students in eleventh grade high school class. There are 40 students in the soccer team and 50 students in the bask

bekas [8.4K]

Answer:

P(A) = 0.2

P(B) = 0.25

P(A&B) = 0.05

P(A|B) = 0.2

P(A|B) = P(A) = 0.2

Step-by-step explanation:

P(A) is the probability that the selected student plays soccer.

Then:

$P(A)=\dfrac{40}{200}=0.2$

P(B) is the probability that the selected student plays basketball.

Then:

$P(B)=\dfrac{50}{200}=0.25$

P(A and B) is the probability that the selected student plays soccer and basketball:

$P(A\&B)=\dfrac{10}{200}=0.05$

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

$P(A|B)=\dfrac{P(A\&B)}{P(B)}=\dfrac{10}{50}=0.2$

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.

4 0

2 years ago

Chris built a rectangular snow fort with a perimeter of 24 feet. The length of the fort was 8 feet less than 3 time the width. W

Ira Lisetskai [31]

24= x+y
X= 3y-8
24= 3y-8+y
24=4y-8
32=4y
Y=8
X=16

4 0

1 year ago

1. Find three rational numbers between 7/12 and 7/11

Sonbull [250]

Step-by-step explanation:

In this problem, we need to find three rational numbers between 7/12 and 7/11.

First rational no :