Answer:
(16-9)
Step-by-step explanation:
that is the answer because 16-9 is 7
Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg
Answer: 15.7 minutes
Step-by-step explanation:
Let x be the time in the beginning (in minutes).
Given: The track team is trying to reduce their time for a relay race.
First they reduce their time by 2.1 minutes.
Then they are able to reduce that time by 10
If their final time is 3.96 minutes, then
x-t1-t2= 3.6
x= 3.6+ t1+ t2
x= 3.6+ 2.1+ 10
x= 15.7
Hence, their beginning time was 15.7 minutes.
If you would like to find the matching equation, you can do this using the following steps:
ax^2 + bx + c = 0
a = -2
b = 1
c = 3
-2x^2 + x + 3 = 0
The correct result would be a. 0 = <span>-2x^2 + x + 3.</span>
Add some of them or all of them to your sum of 47.75, if either or exceeds the limit then that is what left out.
