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uysha [10]
1 year ago
5

this net will be folded to form a prism. which pairs of faces will be opposite one another when the prism is created? check all

that apply. A. d and f B. a and c C. a and b D. b and f E. b and e F. b and c G. e and f H. a and f.

Mathematics
1 answer:
lesya [120]1 year ago
6 0

Answer:

  1. d and f   2.a and c  3.b and e

Step-by-step explanation:

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From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri
Leviafan [203]

Answer:

t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32    

The degrees of freedom are given by:

df=n-1=10-1=9  

The p value for this case is given by:

p_v =2*P(t_{(9)}>2.32)=0.0455    

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=201.77 represent the sample mean    

s=2.41 represent the sample standard deviation    

n=10 sample size    

\mu_o =200 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic

p_v represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :    

Null hypothesis:\mu = 200    

Alternative hypothesis:\mu = 200    

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

The statistic is given by:

t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32    

The degrees of freedom are given by:

df=n-1=10-1=9  

The p value for this case is given by:

p_v =2*P(t_{(9)}>2.32)=0.0455    

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

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2 years ago
A film production house surveyed a group of men and women, asking them which genre of film they prefer to watch. This table give
ValentinkaMS [17]
39% of women prefer drama
7 0
1 year ago
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The following numerically ordered sequence of numbers has a mean of 17 and a median of 18.
erastovalidia [21]

Answer:

a = 9

b = 19

Step-by-step explanation:

DO B FIRST

The mean is the average of all the terms (numbers) in the sequence

To find the average you find the sum of the terms and divided the sum by the number of terms there are.

The mean times the number of terms equals the sum of all the terms subtract the terms that you know from the sum to get A

a = 17(10)-7-12-15-17-19-20-22-24-25

a = 170-161

a = 9

The median is found by taking the average of the two middle terms

Our middle terms are 17 and B

the median times 2 equals the sum of the two terms and then subtract the term you know from the sum

b = 18(2)-17

b = 36-17

b = 19

5 0
2 years ago
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Captain Emily has a ship, the H.M.S Crimson Lynx. The ship is five furlongs from the dread pirate Umaima and her merciless band
LenaWriter [7]

Answer:

The probability that the pirate misses the captain's ship but the captain hits = 0.514

Step-by-step explanation:

Let A be the event that the captain hits the pirate ship

The probability of the captain hitting the pirate ship, P(A) = 3/5

Let B be the event that the pirate hits the captain's ship

The probability of the pirate hitting the captain's ship P(B) = 1/7

The probability of the pirate missing the captain's ship, P'(B) = 1 - P(B)

P'(B) = 1 - 1/7 = 6/7

The probability that the pirate misses the captain's ship but the captain hits = P(A) * P(B) = 3/5 * 6/7

= 0.514

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2 years ago
Leo is testing different types of greenhouse material to determine which type is most effective for growing strawberry bushes. H
alexandr1967 [171]

Answer:

Hey there!

This is not a valid experiment because the sunshine each section received were not equal.

Let me know if this helps :)

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2 years ago
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