<h2>Answer:</h2>
A.
Let Annie's weight be = a
Let Benjie's weighs = b
Let Carmen's weight be = c
One day Annie weighed 24 ounces more than Benjie, equation forms:
......(1)
Benjie weighed 3 1/4 pounds less than Carmen.
In ounces:
1 pound = 16 ounces
pounds = 
ounces
or
......(2)
Now adding (1) and (2), we get
a+b=b+24+c-52
=> 
This gives Annie weighs 28 ounces less than Carmen.
B.
We cannot know anyone's actual weight, as we only know their relative weights.
500 grams equals 0.50 kg so multiply 1.76 3 times to get 5.28, then divide 1.76 by 2 to get .88 add the two together to get 6.16
Answer:
13 children and 9 adults if the total cost is $152.5
Step-by-step explanation:
Let x children and y adults
x + y = 22 (1)
5.5x + 9y = 125.5 (2)
y = 22 - x
5.5x + 9(22 - x) = 125.5
5.5x + 198 - 9x = 125.5
-3.5x = 125.5 - 198
-3.5x = -72.5
x = 20.7
y = 22 - x = 1.3
Which is not possible
If the total cost is $152.5
x + y = 22 (1)
5.5x + 9y = 152.5 (2)
y = 22 - x
5.5x + 9(22 - x) = 152.5
5.5x + 198 - 9x = 152.5
-3.5x = 152.5 - 198
-3.5x = -45.5
x = 13
y = 22 - 13 = 9
Answer:
Option a) circle 5 meters and 22 meters
Step-by-step explanation:
We are given the following information in the question:
A pair of diameter and the circumference is given. We have to find a correct approximations for the diameter and circumference.
a) circle 5 meters and 22 meters
b) 19 inches and 50 inches
c) 33 centimeters and 80 centimeters
Thus, no pair gives a reasonable approximation. Only the circle with diameter 5 and circumference 22 meters have closest approximation.
Answer: The distance between the girls is 362.8 meters.
Step-by-step explanation:
So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.
The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:
Tan(A) = opposite cath/adjacent cath.
Tan(40°) = X/160m
Tan(40°)*160m = 134.3 m
Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°
So we have:
Tan(55°) = X/160m
Tan(55°)*160m = X = 228.5 m
And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:
Dist = 228.5m + 134.3m = 362.8m
