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Ket [755]
1 year ago
14

Seven Applicants for a Job - F, G, H, I, J, K, and L are each to be interviewed on monday or Tuesday . Each

Mathematics
1 answer:
stiks02 [169]1 year ago
6 0

Answer:

I would guess its D. Because it is the one that makes the most sense.

Step-by-step explanation:

H and L has to be on the same day with no other application so not A, B, or C because there is L in all of them.

Hope I helped!

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Tricia saved money, but the amount she saved didn't meet both her emergency needs and savings for her goal. Which of these would
Hoochie [10]
Tricia should take the money that she already has saved no matter how little it is and split it evenly between savings and emergency needs
6 0
2 years ago
Read 2 more answers
If FG = 2 units, FI = 7 units, and HI = 1 unit, what is GH? 3 units 4 units 5 units 6 units
Nezavi [6.7K]
I think the points given here are plotted linearly: 

FGHI. in this case, we can tell that FG + GH + HI = FI. substituting to the expression devised, 2 units + GH + 1 unit = 7 units. This is equal to 3 units + GH = 7 units. GH is then equal to 4 units.

5 0
2 years ago
Read 2 more answers
Your cell phone plan charges a base charge each month plus a charge per daytime minute of usage and December used 510 daytime mi
algol13

Answer:

In February, 423 daytime minutes is used

Step-by-step explanation:

Let the base plan charges be x

And cost per daytime minute be y

In December,

x  + 510y =  92.25------------------(1)

In January,

x + 397y = 77.56---------------------(2)

Subtracting eq(2) from eq(1)

x  + 510y =  92.25

x + 397y = 77.56

-------------------------------

0  + 113y = 14.69

-------------------------------

y = \frac{14.69}{113}

y =  0.13----------------------------------(3)

Substituting (3) in (1)

x  + 510(0.13) =  92.25

x + 66.3 = 92.25

x = 92.25 - 66.3

x = 25.95

So In February

base plan  + (daytime minute)(cost per daytime minute) = 80.9

25.95 + (daytime minute)(0.13) = 80.9

(daytime minute)(0.13) = 80.9 - 25.95

(daytime minute)(0.13) = 54.95

(daytime minute) =\frac{54.95}{0.13}

daytime minutes = 422.69

daytime minute  \approx 423

3 0
2 years ago
I need help with number 5 please
steposvetlana [31]

Answer: Would be 55% I hope this helps!

7 0
2 years ago
Read 2 more answers
The height of seaweed of all plants in a body of water are normally distributed with a mean of 10 cm and a standard deviation of
Degger [83]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: height of seaweed.

X~N(μ;σ²)

μ= 10 cm

σ= 2 cm

You have to find the value of the variable X that separates the bottom 0.30 of the distribution from the top 0.70

P(X≤x)= 0.30

P(X≥x)= 0.70

Using the standard normal distribution you have to find the value of Z that separates the bottom 0.30 from the top 0.70 and then using the formula Z= (X-μ)/σ translate the Z value to the corresponding X value.

P(Z≤z)= 0.30

In the body of the table look for the probability of 0.30 and reach the margins to form the Z value. The mean of the distribution is "0" so below 50% of the distribution you'll find negative values.

z= -0.52

Now you have to clear the value of X:

Z= (X-μ)/σ

Z*σ= X-μ

X= (Z*σ)+μ

X= (-0.52*2)+10= 8.96

The value of seaweed height that divides the bottom 30%  from the top 70% is 8.96 cm

I hope this helps!

7 0
2 years ago
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