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2 years ago

Find the coordinates of the point whose ordinate is -7 and lies on y axis

Mathematics

1 answer:

Alika [10]2 years ago

5 0

Answer:

(0,-7)

Step-by-step explanation:

If nay point is form (x,y)

x is abscissa can be also called x axis coordinate

y is ordinate can be also called y axis coordinate

ordiantes are points lying on y axis.

For any point lying on y axis, its x-axis coordinate will be 0

given that ordinate is -7. it means that value of y coordinate is -7

Thus, coordinates of the point is (0,-7)

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herlene has 5.05 in quarters and dimes. The number of quarters is one more than twice the number of dimes. Find the number she h

VLD [36.1K]

Answer:

<em>Herlene has 8 dimes and 17 quarters</em>

Step-by-step explanation:

<u>System of Equations</u>

Let's call:

x = number of dimes Herlene has

y = number of quarters Herlene has

Since each dime has a value of $0.10 and each quarter has a value of $0.25, the total money Herlene has is 0.10x+0.25y.

We know this amount is $5.05, thus:

0.10x + 0.25y = 5.05 [1]

It's also given the number of quarters is one more than twice the number of dimes, i.e.:

y = 2x + 1 [2]

Substituting in [1]:

0.10x + 0.25(2x + 1) = 5.05

Operating:

0.10x + 0.5x + 0.25 = 5.05

0.6x = 5.05 - 0.25

0.6x = 4.8

x = 8

From [2]:

y = 2*8 + 1 = 17

y = 17

Herlene has 8 dimes and 17 quarters

4 0

1 year ago

terrence made a sphere out of modeling clay. the sphere had a radius of 2 inches. approximately how much modeling clay did terre

navik [9.2K]

Amount of clay used = volume of the sphere

It is given that the radius of the sphere is 2 inches.

Volume of the sphere = $\frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi (2^{3} )$

$=\frac{4}{3} \pi (8)$

$=\frac{32}{3} \pi$

Hence, the amount of modeling clay Terrence used $=\frac{32}{3} \pi$ cubic inches.

5 0

1 year ago

Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is

Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

$(x^2-12x+35)(x^2+10x+24)=504$

We have to find the sum of positive roots of the equation.

$x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504$

$x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504$

$x^4-2x^3-61x^2+62x+840-504=0$

$x^4-2x^3-61x^2+62x+336=0$

Factor of 336

2,3,4,6,8,7,

Let x=2

$2^4-2^4-61(2^2)+62(2)+336\neq0$

x=2 is not the root of equation

x=-2

$(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0$

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

$3^4-2(3^3)-61(3^2)+62(3)+336=0$

Therefore, x=3 is the root of equation.

$(x+2)(x-3)(x^2-x-56)=0$

$(x+2)(x-3)(x^2-8x+7x-56)=0$

$(x+2)(x-3)(x(x-8)+7(x-8))=0$

$(x+2)(x-3)(x-8)(x+7)=0$

$x-8=0\implies x=8$

$x+7=0\implies x=-7$

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0

1 year ago

Which phrase best describes the translation from the graph y = 2(x – 15)2 + 3 to the graph of y = 2(x – 11)2 + 3? 4 units to the

Mama L [17]

Left is plus right is negative -11-(-15)=4 so you know 4 to the left

8 0

1 year ago

Read 2 more answers

High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

mamaluj [8]

Answer:

The 95% confidence interval the average maximum power is (596.0 to 644.0)

Step-by-step explanation:

Average maximum of the sample = x = 620 HP

Standard Deviation = s = 45 HP

Sample size = n = 16

We have to calculate the 95% confidence interval. The value of Population standard deviation is unknown, and value of sample standard deviation is known. Therefore, we will use one sample t-test to build the confidence interval.

Degrees of freedom = df = n - 1 = 15

Critical t-value associated with 95% confidence interval and 15 degrees of freedom, as seen from t-table = $t_{\frac{\alpha}{2}}$ = 2.131

The formula to calculate the confidence interval is:

$(x-t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} }, x+t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} })$

We have all the required values. Substituting them in the above expression, we get:

$(620-2.131 \times \frac{45}{\sqrt{16} }, 620+2.131 \times \frac{45}{\sqrt{16} })\\\\ =(596.0 , 644.0)$

Thus, the 95% confidence interval the average maximum power is (596.0 to 644.0)

7 0

2 years ago

Find the coordinates of the point whose ordinate is -7 and lies on y axis​

Find the coordinates of the point whose ordinate is -7 and lies on y axis