All categories

2 years ago

Solve 2+1^6y=3x+4 for y.

Mathematics

1 answer:

kow [346]2 years ago

8 0

Here you go this is all you are doing

You might be interested in

Which arrangement shows −275 , −4.1 , −535 , and −3 in order from least to greatest?

vodomira [7]

Answer:

-535, -275, -4.1, -3

Step-by-step explanation:

6 0

1 year ago

Tickets to a play are $12.00 for adults. Children receive a discount and only have to pay $8.00. If 40 people attend the play an

MrRa [10]

30 were adults and 10 were children :) just add it up

3 0

1 year ago

An object was moving at a rate of 18.2 feet per second for 38.5 seconds. How far did the object travel?

lidiya [134]

Answer:

700.7

Step-by-step explanation:

You're looking for distance. So all you have to do is 18.2 x 28.5 and you'll get your answer.

Hope this helps. :)

4 0

2 years ago

PLEASE HELP NEED TO PASS!!!!!!!!The graph shows the relationship between the number of ounces of cereal in a box and the price o

Sergio039 [100]

For this case, the first thing we must do is observe the relationship between the variables:

Independent variable: Weight of the box (ounces)

Dependent variable: Price of the box ($)

Observing the behavior between both variables, we see that there is no specific relationship between the increase or decrease in the weight of the box and the increase or decrease in the price.

Therefore, there is no correlation between the variables.

Answer:

the correlation between the weight and price of a box of cereal is:

none

4 0

2 years ago

Read 2 more answers

Which of the following is the expansion of (3c + d2)6?

vovangra [49]

Answer: Option A) $729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$ is the correct expansion.

Explanation:

on applying binomial theorem, $(a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r$

Here a=3c, $b=d^2$ and n=6,

Thus, $(3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r$

⇒ $(3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6$

⇒ $(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}$

⇒ $(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}$

⇒ $(3c+d^2)^6=729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$

3 0

2 years ago

Read 2 more answers