Answer:
1. Group C; 2. Group B; 3. Group D; 4. Group A
Step-by-step explanation:
These equations are in the form
, where v₀ is the initial velocity and h₀ is the initial height.
The first equation has no value for v₀ and a value of 19 for h₀. This means there is no velocity, so the ball is dropped, and since the initial height is 19, it is dropped from 19 meters. This makes it group C.
The second equation has a value of 50 for v₀ and no value for h₀. This means the initial velocity is 50 and there is no initial height. This makes it group B.
The third equation has no value for v₀ and a value of 50 for h₀. This means there is no initial velocity, so the ball is being dropped, and the initial height is 50. This makes it group D.
The fourth equation has a value of 19 for v₀ and no value for h₀. This means the initial velocity is 19 and there is no initial height. This makes it group A.
I cant really help you with the table but she will need $14.40 to pay for it. This is because since two cups cost $3.60 you multiply 3.60 by 4. I got the 4 by dividing 8 into 2 because 8 people and 2 cups each
Answer:
For the critical value we need to calculate the degrees of freedom given by:
And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:
Step-by-step explanation:
Previous concepts
A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.
Let put some notation
x=test value with right arm , y = test value with left arm
The system of hypothesis for this case are:
Null hypothesis: 
Alternative hypothesis: 
The first step is calculate the difference 
The second step is calculate the mean difference
The third step would be calculate the standard deviation for the differences, and we got:
The 4 step is calculate the statistic given by :
For the critical value we need to calculate the degrees of freedom given by:
And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:
Answer:
68.04
Step-by-step explanation:
We have
1.234 in-----> 1+(0.234) in
we know that
1/64=0.015625
so
0.234/0.015625=14.98-----> 15
15/64-----> 0.234
therefore
1.234 in is equal to -----------> 1 15/64 in
the answer is
1 15/64 in
