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ruslelena [56]
2 years ago
13

Of the coffee makers sold in an appliance​ store, 4.0% have either a faulty switch or a defective​ cord, 2.5% have a faulty​ swi

tch, and​ 0.1% have both defects. What is the probability that a coffee maker will have a defective​ cord? Express the answer as a percentage.
Mathematics
1 answer:
lukranit [14]2 years ago
6 0

Answer: Hence, Probability that a coffee maker will have a defective cord is 0.376=37.6%.

Step-by-step explanation:

Since we have given that

Let A be the event of getting a faulty switch.

Let B be the event of getting a defective cord.

Here, P(A∪B) = 4% = 0.04

P(A∩B) = 0.1% = 0.001

P(A) = 2.5% = 0.025

We need to find P(B):

As we know that

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\0.04=P(A)+0.025-0.001\\\\0.04=P(A)+0.024\\\\P(A)=0.04-0.024=0.376

Hence, Probability that a coffee maker will have a defective cord is 0.376=37.6%.

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Step-by-step explanation:

The random variable is the amount of years that have higher average temperatures than its previous year.

As the sample is from 5 years, the random variable can take values from 0 (where none of the years increase their average temperature from its previous year) to 4 (where every year increases the average temperature).

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In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa
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Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

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So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

Step-by-step explanation:

Data given and notation  

X_{1}=25 represent the number of homeowners who would buy the security system

X_{2}=9 represent the number of renters who would buy the security system

n_{1}=140 sample 1

n_{2}=60 sample 2

p_{1}=\frac{25}{140}=0.179 represent the proportion of homeowners who would buy the security system

p_{2}=\frac{9}{60}= 0.15 represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>0.500)=0.617  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

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