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laiz [17]
1 year ago
8

Sam has been asked to prepare 40 documents in 2 work days(there are 8 hours in each workday).Each document takes 30 minutes to p

repare.Assuming Sam works both days,how many hours of help will he need to finish in 2 work days?
Mathematics
1 answer:
sladkih [1.3K]1 year ago
7 0

Answer:n 2 work days, there are 8 hours in each workday. How many hours of help will he need in 2 work days

Step-by-step explanation:

You might be interested in
.
sveta [45]

Answer:

Hayden's hourly rate is $30

Extra hour rate is 1.5×30=$45

given that he earned $2175 by working 40 regular hours, the number of overtime hours he worked will be given as follows;

let the number of overtime be x

hence total amount earned will be:

(40×30)+(45×x)=2175

1200+45x=2175

45x=2175-1200

45x=975

solving for x we get

x=975/45

x=65/3=21 2/3 hours  

 

Therefore the answer is c.562.50

Step-by-step explanation:

brainliest please

8 0
2 years ago
Which expressions are equivalent to 5 x minus 15? Select three options. 5 (x + 15) 5 (x minus 3) 4 x + 3 y minus 15 minus 3 y +
Aleksandr [31]

Answer:

B) 5 (x minus 3)

C) 4 x + 3 y minus 15 minus 3 y + x

E) Negative 20 minus 3 x + 5 + 8 x

tep-by-step explanation:

5x minus 15

5x - 15

5(x - 3)

4 x + 3 y minus 15 minus 3 y + x

4x + 3y - 15 - 3y + x

5x - 15

Negative 20 minus 3 x + 5 + 8 x

-20 - 3x + 5 + 8x

5x - 15

6 0
2 years ago
Read 2 more answers
Consider the continuous random variable X, which has a uniform distribution over the interval from 20 to 28.
anastassius [24]

Answer:

a) The probability distribution is f(x) = \frac{1}{8}

b) 0.5 = 50% probability that X will take on a value between 21 and 25.

c) 0.25 = 25% probability that X will take on a value of at least 26.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{a - x}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

Uniform distribution over the interval from 20 to 28.

This means that a = 20, b = 28

a. What’s the probability density function?

The probability density function of the uniform distribution is:

f(x) = \frac{1}{b - a}

In this question:

f(x) = \frac{1}{28 - 20} = \frac{1}{8}

b. What’s the probability that X will take on a value between 21 and 25?

P(21 \leq X \leq 25) = \frac{25 - 21}{28 - 20} = \frac{4}{8} = 0.5

0.5 = 50% probability that X will take on a value between 21 and 25.

c. What’s the probability that X will take on a value of at least 26?

P(X > 26) = \frac{28 - 26}{28 - 20} = \frac{2}{8} = 0.25

0.25 = 25% probability that X will take on a value of at least 26.

4 0
2 years ago
Multiply the number by 4. Add 12 to the product. Divide this sum by 2. Subtract 6 from the quotient. 1st number is 3 and the res
jolli1 [7]

N = original number = 6
6 0
2 years ago
Prove algebraically that the recurring decimal 0.472 can be written as<br> 17<br> 36
Katen [24]

Given:

The recurring decimal is 0.47\overline{2}.

To prove:

Algebraically that the recurring decimal 0.47\overline{2} can be written as \dfrac{17}{36}.

Proof:

Let,

x=0.47\overline{2}

x=0.472222...

Multiply both sides by 100.

100x=47.2222...     ...(i)

Multiply both sides by 10.

1000x=472.2222...        ...(ii)

Subtract (i) from (ii).

1000x-100x=472.2222...-47.2222...

900x=425

Divide both sides by 900.

x=\dfrac{425}{900}

x=\dfrac{17}{36}

So, 0.47\overline{2}=\dfrac{17}{36}.

Hence proved.

8 0
2 years ago
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