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liq [111]
2 years ago
5

Joey is planning to invest his savings in a fixed income fund. He manages to deposit $700 at the end of the first year, $500 at

the end of the second year, $300 at the end of the third year, and $600 at the end of the fourth year. If the fund earns 6 percent interest each year, the terminal value of this uneven cash flow stream at the end of Year 4 is _____.
Mathematics
1 answer:
insens350 [35]2 years ago
8 0

Answer:

$2313.51

Step-by-step explanation:

Here we calculate the future value for each cash flow and add them up.

Given he deposited $700 at the end of the first year .

Here time to maturity is 3years and interest rate is 6%.

FV=C(1+r)^{t}=   700(1+0.06)^3=$833.71

Given he deposited $500 at the end of the second year .

Here time to maturity is 2 years and interest rate is 6%.

FV=C(1+r)^{t}=   500(1+0.06)^2=$561.8.

Given he deposited $300 at the end of the third year .

Here time to maturity is 1years and interest rate is 6%.

FV=C(1+r)^{t}=   300(1+0.06)^1=$318.

Also given that he deposited $600 at the end of fourth year .There will be no interest on this amount as it is done at the end.

Terminal value=833.71+561.8+318+600=$2313.51

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The table below shows the total cost of buying printer ink cartridges for both members and nonmembers of a shopping club. Price
ki77a [65]

Answer:

B

Step-by-step explanation:

3 0
2 years ago
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A researcher collects a simple random sample of​ grade-point averages of statistics​ students, and she calculates the mean of th
anyanavicka [17]

Answer:

a. The sample has more than 30 grade-point averages.

Step-by-step explanation:

Given that a researcher collects a simple random sample of​ grade-point averages of statistics​ students, and she calculates the mean of this sample

We are asked to find the conditions under which  that sample mean can be treated as a value from a population having a normal​ distribution

Recall central limit theorem here

The central limit theorem states that the mean of all sample means will follow a normal distribution irrespective of the original distribution to which the data belonged to provided that

i) the samples are drawn at random

ii) The sample size should be atleast 30

Hence here we find that the correct conditions is a.

Only option a is right

a. The sample has more than 30 grade-point averages.

7 0
2 years ago
Part A What is the electric field at the position (x1,y1)=(5.0 cm , 0 cm) in component form? Express your answer in terms of the
erik [133]

The complete Question is

A −12 nC charge is located at (x, y)=(1.0 cm, 0 cm).

Part A) What is the electric field at the position (x1, y1)=(5.0 cm, 0 cm) in component form?

Part B) What is the electric field at the position (x2, y2)=(−5.0 cm, 0 cm) in component form?

Part C) What is the electric field at the position (x3, y3)=(0 cm, 5.0 cm) in component form?

Express your answer in terms of the unit vectors i^ and j^. Use the 'unit vector' button to denote unit vectors in your answer.

Answer:

A)  E = - 67500i + 0j N/C

B)   E = 30000i + 0j N/C

C)  E = 8143.18i -  -40715.66j N/C

Step-by-step explanation:

Part A)

Magnitude of the charge = Q = -12 nC = -12 \times 10^{-9} C

Since, its the negative charge, the direction of Electric Field lines will be directed toward the charge

Location of the charge = (1, 0)

We need to find the electric field at point (5, 0)

The formula for the magnitude of electric field due to a point charge is:

E=\frac{kQ}{r^{2}}

Here,

k = Coulomb's Law Constant = 9 \times 10^{9}

Q = Magnitude of the charge

r = Distance between the charge and the point where we need to find the value of E

We can find r by using the Distance Formula.

So,

r=\sqrt{(5-1)^{2}+(0-0)^{2}}=4 cm = 0.04 m

Using these values in the formula, we get:

E=\frac{9\times 10^{9} \times 12 \times 10^{-9}}{(0.04)^{2}}= 67500 N/C

Since, two point (5, 0) is to the right of the given charge (as shown in the first image) i.e. in horizontal direction, all of the electric field experienced by it will be in horizontal direction and the vertical component would be zero. Also the direction of Electric field will be towards the charge i.e. in left direction so the x-component of Electric field will be negative.

Thus, we can write the value of E in vector form to be:

E = - 67500i + 0j N/C

Part B)

We need to find the Electric Field at point (-5, 0)

Using the similar procedure as used in the previous step, first we find r:

r=\sqrt{(-5-1)^{2}+(0-0)^{2}}=6 cm = 0.06

Using the values in the formula of Electric field, we get:

E = \frac{9 \times 10^{9} \times 12 \times 10^{-9}}{(0.06)^2}=30000 N/C

In this case again, the point is located in a horizontal direction to the given charge, so all the Electric Field experienced by it will be in horizontal direction and the vertical component will be zero. The direction of Electric field will be towards the charge i.e towards Right, so the x-component will be positive in this case.

So, value of the electric field in component form would be:

E = 30000i + 0j N/C

Part C)

We need to find the value of electric field at the point (0, 5). First we find the value of r:

r=\sqrt{(1-0)^2+(0-5)^2}=\sqrt{26}=5.1 cm = 0.051 m

Using the values in the formula of E, we get:

E=\frac{kQ}{r^{2}}=\frac{9 \times 10^{9} \times 12 \times 10^{-9}}{(0.051)^{2}}=41522 N/C

The point (0, 5) is neither exactly to the left or exactly up. So, for this point we need to find both the horizontal and vertical components as shown in the 2nd figure below.  

From the triangle, we have the opposite and adjacent side to the angle, so using the tangent we can find the value of angle theta.  

tan(\theta)=\frac{5}{1}\\\theta=tan^{-1}(5)=78.69

The two angles shown in the figure will be equal as there are alternate interior angles. Now the angle which E will make with positive x-axis will lie in the 4th quadrant as it lies below the horizontal line. So, the angle with positive x-axis would be:

360 - 78.69 = 281.31 degrees

Ex = E cos(θ) = 41522 cos(281.31) = 8143.18 N/C

Ey = E sin(θ) = 41522 sin(281.31) = -40715.66 N/C

So, in component form the Electric field will be:

E = 8143.18<em>i</em> -  -40715.66<em>j</em>

3 0
2 years ago
14. Marian wants to buy a double scoop of ice cream. The ice cream shop has 23 flavours, which can be served in a regular cone,
aksik [14]

Answer:

Marian can order 1,771 combinations

Step-by-step explanation:

In this question, we are interested in calculating the number of combinations Marian can order given that there are 23 flavors that can be served in three ways.

Mathematically, the number of combinations that can be ordered is simply 23C3

This is equal to 23!/(23-3)!3! = 23!/20!3! = 1,771

The number of combinations she can order is thus 1,771 combinations

3 0
2 years ago
Shalise competed in a jigsaw puzzle competition where participants are timed on how long they take to complete puzzles of variou
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Answer:

16% on the small puzzle and 84% on the large puzzle.

Step-by-step explanation:

3 0
2 years ago
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