Question

A piece of machinery loses $20 in value every month. Its value after m months of service is $1475. Which is the rate of change in this situation?

Answer 1

Answer: $Rate\ of\ change=20$

Step-by-step explanation:

The Slope-Intercept form of an equation of a line is the following:

$y=mx+b$

Where "m" is the slope of the line and "b" is the y-intercept.

By definition, the slope is:

$m=\frac{change\ in\ y}{change\ in\ x}$

Since the rate of change shows how a quantity changes in relation to another quantity, this is:

$Rate\ of\ change=m=\frac{change\ in\ y}{change\ in\ x}$

You must remember that It is a constant.

According to the information given in the exercise, a piece of the machinery loses $20 in value every month (Notice that this is constant) and its value after "m" months of service is $1,475.

Therefore, you can identify that:

$m=20$

Then, you get that the rate of change in this situation is:

$Rate\ of\ change=m=20$