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Nimfa-mama [501]
2 years ago
6

Lina is going to plant 63 tomato plants and 81 rhubarb plants. Lina would like to plant ,the plants in rows where each row has t

he same number of tomato plants and each row has the same number of rhubarb plants. What is the greatest number of rows Lina can plant?
Mathematics
1 answer:
Aleks04 [339]2 years ago
8 0

Answer: 9

Step-by-step explanation:

Given : Lina is going to plant 63 tomato plants and 81 rhubarb plants.

i.e. Total tomato plants = 63

Total rhubarb plants.  =81

If Lina would like to plant , the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants.

Then, the greatest number of rows Lina can plant = Greatest common factor of 63 and 81.

Prime factorization of 63 and 81:

63=3\times3\times7\\\\ 81=3\times3\times3\times3

Greatest common factor of 63 and 81 = 3\times3=9

So , the greatest number of rows Lina can plant= 9

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Answer:

0.4007

Step-by-step explanation:

Let's define the following events:

A: method A is used

B: method B is used

NR: the eye has not recovered in a month

R: the eye is recovered in a month

The probability that the eye has not recovered in a month is 0.002 if method A is used, i.e., P(NR|A) = 0.002, so P(R|A) = 0.998.

When method B is used, the probability that the eye has not recovered in a month is 0.005, i.e., P(NR|B) = 0.005, so P(R|B) = 0.995.

40% of eye surgeries are done with method A, i.e., P(A) = 0.4

60% of eye surgeries are done with method B, i.e., P(B) = 0.6

If an eye is recovered in a month after surgery is done in the hospital, what is the probability that method A was performed? We are looking for P(A|R), then, by Bayes' Formula

P(A|R) = P(R|A)P(A)/(P(R|A)P(A) + P(R|B)P(B)) = 0.998*0.4/(0.998*0.4 + 0.995*0.6) = 0.4007

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2 years ago
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skelet666 [1.2K]

Answer:

0.0021

Step-by-step explanation:

Given:

Probability of ordering a nonalcoholic beverage is, P(N)=0.46

Number of samples are n=10

Now, the complement of event 'N' is not ordering a nonalcoholic beverage.

Therefore, P(\overline N)=1-P(N)=1-0.46=0.54

Now, for a sample of '10' customers, the probability of not ordering a non alcoholic beverage is product of their individual probabilities as all these events are independent events.

Therefore, probability that none of the 10 will order a nonalcoholic beverage is given as:

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Complete Question: Check the file attached to this document to see the complete question

Answer:

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Step-by-step explanation:

Counting properly from the diagram attached to the question,

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