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Tems11 [23]
2 years ago
10

A developer needs to create a visualforce page that displays case data. The page will be used by both support reps and support m

anagers. The support rep profile does not allow visibility of the customer_Satisfaction_c Field, but the support manager profile does. How can the developer create the page to enforce field level security and keep future maintenance to a minimum?A. Create one visualforce page for use by both profilesB. Use a new support manager permission setsC. Create a separate visualforce page for each profileD. Use a custom controller that has the with sharing keywords
Computers and Technology
1 answer:
shutvik [7]2 years ago
7 0

Answer:

B. Use a new support manager permission sets

Explanation:

According to the requirements, field level security is required so, 1st options is not suitable because it may reduce the maintenance cost but increase the risk of security.

By creating a separate page for each of the two, it will leads to increase in the maintenance cost of the system. So <u>Option C</u> is also not suitable.

Option B is more Suitable as compared to others, that <em>Create a new support manager permission set</em>, with the help of this, both of Support rep and Support manager can visualize their required information with the help of support manager permission. This solution will not compromise the security and not increase the maintenance cost.

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The Company management has asked that you compare the OSSTMM and the PTES to determine which methodology to select for internal
Sonbull [250]

Answer:

The basic comaprism of OSSTMN and PTES includes the following: OSSTMN is more theoretical, security assessment methodology, and Metrics based why PTES is technology oriented, penetration testing methodology ,  extended analysis of all stages

Explanation:

Solution

Penetration testing has several methodologies which include :OSSTMM and PTES  

The comparison between OSSTMM and PTES is stated as follows:

OSSTMM:                                                

Security assessment methodology

More Theoretical  

Metrics based

PTES :

Technology oriented

Penetration testing methodology

Extended analysis of all stages

Now,

There are 7 stages which is used to define PTES for penetration testing.(Penetration Testing Execution Standard)

  • Pre-engagement Interactions
  • Intelligence Gathering
  • Threat Modeling
  • Vulnerability Analysis
  • Exploitation
  • Post Exploitation
  • Reporting

Now,

The OSSTMM is used to obtain security metrics and performing penetration testing .The OSSTMM provides transparency to those who have inadequate security policies and configurations.

The OSSTMM includes the entire risk assessment process starting from requirement analysis to report creation.

Six areas are covered by OSSTMM which are:

  • Information security
  • Process security
  • Internet technology security
  • Communications security
  • Wireless security
  • Physical security
7 0
2 years ago
A laptop gets replaced if there's a hardware issue. Which stage of the hardware lifecycle does this scenario belong to?
Ilya [14]

Answer: Maintenance. This is the stage where software is updated and hardware issues are fixed if and when they occur. Retirement. In this final stage, hardware becomes unusable or no longer needed and it needs to be properly removed from the fleet

Explanation:

3 0
2 years ago
In this problem we consider sending real-time voice from Host A to Host B over a packet-switched network (VoIP). Host A converts
Minchanka [31]

Answer:

<u>The total time elapsed from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B is </u><u>25.11 ms</u>

Explanation:

Host A first converts the analog signal to a digital 64kbps stream and then groups it into 56-byte packets. The time taken for this can be calculated as:

time taken 1= \frac{Packet Size in Bits}{Bit Rate}

                 = (56 x 8) bits / 64 x 10³ bits/s

                 = 7 x 10⁻³s

time taken 1= 7 ms

The transmission rate of the packet from Host A to Host B is 4 Mbps. The time taken to transfer the packets can be calculated as:

time taken 2= (56 x 8) bits / 4 x 10⁶ bits/s

                    = 1.12 x 10⁻⁴ s

time taken 2= 112 μs

The propagation delay is 18 ms.

To calculate the total time elapsed, we need to add up all the time taken at each individual stage.

<u />Time_{total}<u> = Time taken 1 + Time taken 2 + Propagation Delay</u>

                 = 7 ms + 112 μs + 18 ms

                 = 0.025112 s

Time_{total} = 25.11 ms

5 0
2 years ago
Edhesive unit 2 lesson 5 coding activity 1 Write code which creates three regular polygons with 11, 14 and 19 sides respectively
SVEN [57.7K]

Answer:

public class Polygon {

   private String name;

   private int sides;

   private double sideLength;

   public Polygon(String name, int sides, double sideLength) {

       if (sideLength <= 0) throw new IllegalArgumentException("Length cannot be zero or negative.");

       if (sides <= 0) throw new IllegalArgumentException("Sides cannot be zero or negative.");

       this.name = name;

       this.sides = sides;

       this.sideLength = sideLength;

   }

   public String getName() {

       return name;

   }

   public void setName(String name) {

       this.name = name;

   }

   public double getSideLength() {

       return sideLength;

   }

   public void setSideLength(double sideLength) {

       if (sideLength <= 0) throw new IllegalArgumentException("Length cannot be zero or negative.");

       this.sideLength = sideLength;

   }

   public int getSides() {

       return sides;

   }

   public void setSides(int sides) {

       this.sides = sides;

   }

   (use the at sign here)Override

   public String toString() {

       return "regular " + name + " with side length " + String.format("%.1f", sideLength);

   }

}

public class TestPolygon {

   public static void main(String[] args) {

       Polygon sides11 = new Polygon("hendecagon", 11, 1);

       Polygon sides14 = new Polygon("tetrakaidecagon", 14, 1);

       Polygon sides19 = new Polygon("enneadecagon", 19, 1);

       System. out. println(sides11);

       System. out. println(sides14);

       System. out. println(sides19);

   }

}

Explanation:

This java source code defines a class that creates a regular polygon based on the number of sides given to it.

Below is a screenshot of the program code and output.

4 0
1 year ago
An administrator wants to create four subnetworks from the network address 192.168.1.0/24. what is the network address and subne
Vitek1552 [10]
<span>There is a total of 32 bits in </span>IPv4 address space. In this case we have /24, which means <span>that 24 bits are contained in the network. So, the </span><span>
subnetwork  is 192.168.1.64
subnet mask 255.255.255.192</span>
8 0
2 years ago
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