Question

If a filesystem has a block size of 4096 bytes, this means that a file comprised of only one byte will still use 4096 bytes of storage. A file made up of 4097 bytes will use 4096*2=8192 bytes of storage. Knowing this, can you fill in the gaps in the calculate_storage function below, which calculates the storage size needed for a given filesize?
def calculate_storage(filesize):
block_size = 4096
# Use floor division to calculate how many blocks are fully occupied
full_blocks = _
# Use the modulo operator to check whether there's any remainder
partial_block =
# Depending on whether there's a remainder or not, return the right number.
if partial_block > 0:
return
return ___ Run

print(calculate_storage(1)) # Should be 4096
print(calculate_storage(4096)) # Should be 4096
print(calculate_storage(4097)) # Should be 8192 Reset

Answer 1

Answer:

Python code given below

Explanation:

def calculate_storage(filesize):

   block_size = 4096

   full_blocks = filesize // block_size

   partial_block = filesize % block_size

   if partial_block > 0:

       return (full_blocks + 1) * block_size

   return filesize

print(calculate_storage(1))

print(calculate_storage(4096))

print(calculate_storage(4097))

Answer 2

Answer:

The response resonates with a python code that is shown in the explanation below

Explanation:

def calculate_storage(filesize):

 block_size = 4096

  full_blocks = filesize // block_size

  partial_block = filesize % block_size

  if partial_block > 0:

      return (full_blocks + 1) * block_size

  return filesize

print(calculate_storage(1))

print(calculate_storage(4096))

print(calculate_storage(4097))