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gogolik [260]
2 years ago
10

You work for a car rental agency and want to determine what characteristics are shared among your most loyal customers. To do th

is, you will want to use the data mining software you are using to do which of the following?
a. identifying association
b. identifying clusters
c. classification
d. identifying sequences
Computers and Technology
1 answer:
BigorU [14]2 years ago
6 0

Answer:

c. classification

Explanation:

In the given situation, since you want to know what attributes shared among the most loyal customers for this you want to use the data mining software that refers to convert the raw data into the useful information so that it could become meaningful for the organization

In order to know about the characteristics we have to use the classification so that we get to know the characteristics i.e shared among the trusted customers

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Jorge saw a computer named Watson on the game show Jeopardy and was surprised at how many answers Watson was able to get correct
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Answer:

The above statement is FALSE

Augmented reality works with sensor based inputs from the real world.

It is an immersive perception of a real-world environment in which objects existing in the real world are augmented by computer-generated perceptual knowledge, often through multiple sensory modalities like visual, auditory, haptic, somatosensory and olfactory.

Based on the above description

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How do you download a video from sendvid
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You copy the url and paste it in the box on the website

5 0
2 years ago
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Write code that uses the input string stream inss to read input data from string userinput, and updates variables usermonth, use
mr Goodwill [35]

Answer:

It will be a java code.

Explanation:

import java.util.Scanner;

public class StringInputStream {

    public static void main (String [] args) {

        Scanner inSS = null;

        String userInput = "Jan 12 1992";

        inSS = new Scanner(userInput);`

        String userMonth = "";

        int userDate = 0;

        int userYear = 0;

        /* Your solution goes here  */

        System.out.println("Month: " + userMonth);

        System.out.println("Date: " + userDate);

        System.out.println("Year: " + userYear);

        return;

   }

}

3 0
2 years ago
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Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re
aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)    

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=2.938

The sample deviation calculated s=0.472

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.78

Now we have everything in order to replace into formula (1):

2.938-2.78\frac{0.472}{\sqrt{5}}=2.351    

2.938+2.78\frac{0.472}{\sqrt{5}}=3.525    

So on this case the 95% confidence interval would be given by (2.351;3.525)    

5 0
2 years ago
Write an application that allows a user to enter any number of student quiz scores until the user enters 99. If the score entere
maria [59]

Answer:

import java.util.Scanner;

import java.util.*;

import java.util.Collections;

class Main

{

public static void main(String[] args)  

{

     List<Integer> Scores = new ArrayList<Integer>();

     Scanner sc1=new Scanner(System.in);

     int i =0;

     int a=0;

     do

     {

       System.out.println("Enter score");

       a =sc1.nextInt();

       if (a <= 0)

       {

           System.out.println("You entered wrong score");

           continue;

       }

       else if ( a < 10 && a >0)

       {

           System.out.println("You entered wrong score");

           continue;

           

       }

       else

       {

           Scores.add(a);

       }

       i++;

     }while(a!=99);

     int max= Collections.max(Scores);

     int min=Collections.min(Scores);

     int sum=0;

     float averg =0;

     for(i=0; i<=Scores.size()-1;i++)

     {

        sum += Scores.get(i);

     }

     averg= sum/Scores.size();

     System.out.println("Maximum score" +max);

      System.out.println("Minimum score"+min);

     System.out.println("Average:"+averg);

   

}

}

Explanation:

Remember we need to use Arraylist and not array, as we do not know how many scores we are going to have. And we use Collections for this, where we have functions for finding maximum and minimum for arraylist, however, for average, we need to calculate. However, one should know that Arraylist has better options available as compare to arrays.

3 0
2 years ago
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