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maks197457 [2]
2 years ago
11

Suppose a switch is built using a computer work station and that it can forward packets at a rate of 500,000 packets per second,

regardless (within limits) of size. Assume the workstation uses direct memory access (DMA) to move data in and out of its main memory, which has a bandwidth of 2 Gbps, and that the I/O bus has a bandwidth of 1 Gbps. At what packet size would the bus bandwidth become the limiting factor
Computers and Technology
1 answer:
Marina86 [1]2 years ago
3 0

Answer:

When the transmission exceeds 667 packets

Explanation:

In computer networking, a packet is a chunk of data transmitted across the network. The packet size of an Ethernet network is 1.5kilobytes, while the packet size of an IP packet payload is 64 kilobytes.

A switch is a physical network device that connects nodes or workstations while communicating the packets (or frames). The I/O bus size bandwidth is 1Gbps which allows approximately 667 packets. Once this packet size is crossed, the bus becomes a limiting factor or bottle neck.

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2 years ago
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Alisiya [41]

Answer:

b) Bounded Waiting

Explanation:

int currentThread = 1;

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thread1 { thread2 {

While (true) {

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                     while(thread2Access == true)

                                       {

                                      while(thread1Access == true)

                                       {

                                            If (currentThread == 2) {

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                                                  thread1Access = false; thread2Access = false;

                                                  While (currentThread == 2);

                                                 While (currentThread == 1);

                                                  thread1Access = true; thread2Access = true;

} }

/* start of critical section */ /* start of critical section */

currentThread = 2 currentThread = 1

… ...

/* end of critical section */ /* end of critical section */

thread1Access = false; thread2Access = false;

… ...

} }

} }

} }

It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.

4 0
2 years ago
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ss7ja [257]
I don't believe that there are rules.
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2 years ago
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Answer:

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6 0
2 years ago
Which data type change will require the app builder to perform the additional steps in order to retain existing functionalities?
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Answer:

Option D is the correct option.

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