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igomit [66]
2 years ago
12

In cell M2, enter a formula using a nested IF function as follows to determine first if a student has already been elected to of

fice in a student group, and if not, whether that student meets the qualifications to run in the future: a. If the value in the Elected column is equal to the text "Yes", the formula should display Elected as the text.
Computers and Technology
1 answer:
aleksley [76]2 years ago
8 0

Answer:

Following are the code to this question:

code:

=IF(EXACT(I2,"Yes"),"Elected",IF(EXACT(K2,"Yes"),"Yes","No"))

Explanation:

In the given the data is not defined so we explain only  the above code, but before that, we briefly define working of if the function that can be defined as follows:

  • The If() function, is used only when one of the logical functions and its value must return the value true. or we can say it only return a true value.
  • In the above function, a column "Elected" is used that uses other column values to check this column value is equal if this condition is true it will return "yes" value.

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(NumberFormatException)Write the bin2Dec(String binaryString) method to convert a binary string into a decimal number. Implement
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The following program will be used that prompts the user to enter a binary number as a string and displays decimal equivalent of the string.

<u>Explanation:</u>

NumberFormat.java

import java.util.Scanner;

public class NumberFormat{

public static void main(String[] args) {

      Scanner scan = new Scanner(System.in);

      try{

      System.out.println("Enter a binary string:");

      String s = scan.next();

      int integerValue = bin2Dec(Integer.parseInt(s));

      System.out.println("The decimal value of "+s+" is "+integerValue);

      }

      catch(NumberFormatException e){

          System.out.println(e);

      }

  }  

  public static int bin2Dec(int binaryNumber) throws NumberFormatException{

  int decimal = 0;

  int p = 0;

  try{

  while(true){

  if(binaryNumber == 0){

  break;

  } else {

  int temp = binaryNumber%10;

  decimal += temp*Math.pow(2, p);

  binaryNumber = binaryNumber/10;

  p++;

  }

  }

  }

  catch(NumberFormatException e){

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  }

  return decimal;

  }

}

Output:

Enter a binary string:

1011000101

The decimal value of 1011000101 is 709

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Into which of these files would you paste copied information to create an integrated document?
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D cause you will need to keep up with data also
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2) Complete the get_num_of_characters() function, which returns the number of characters in the user's string. We encourage you
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Explanation:

Number of characters: 46

String with no whitespace: Theonlythingwehavetofearisfearitself.

########################################################

def get_num_of_characters(inputStr):

   count = 0

   for i in range(0,len(inputStr)):

       count = count + 1

   #count = len(inputStr)

   return count

def output_without_whitespace(inputStr):

   #statement = statement.strip()

   statement2 = ' '

   for i in range(0,len(inputStr)):

        if(inputStr[i] == ' '):

           statement2 = statement2

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   inputStr = inputStr.replace(" ", "")

   return statement2

inputStr = input('Enter a sentence or phrase: ')

print()

print('You entered:', inputStr)

num = get_num_of_characters(inputStr)

print()

print('Number of characters:', num)

print('String with no whitespace:',output_without_whitespace(inputStr))

#if __name__ == '__main__':

   # Think I'm supposed to use this if statement

########################################################

'''ERROR MESSAGE WHEN RUNNING TEST

Unit test

0/1

Tests that get_num_of_characters() returns 46 for "The only thing we have to fear is fear itself."

Your output

Enter a sentence or phrase: Traceback (most recent call last):

 File "zyLabsUnitTestRunner.py", line 4, in <module>

   from zyLabsUnitTest import test_passed

 File "/home/runner/local/unit_test_student_code/zyLabsUnitTest.py", line 1, in <module>

   from main import get_num_of_characters

 File "/home/runner/local/unit_test_student_code/main.py", line 19, in <module>

   inputStr = input('Enter a sentence or phrase: ')

EOFError: EOF when reading a line'''

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