All categories

2 years ago

In a team, if someone gets stuck with the selected tasks for the iteration, what is the immediate next step?

Business

1 answer:

Serggg [28]2 years ago

5 0

Answer:

a. Without wasting time, the team member has to inform the Lead/Onsite coordinator and take up another task.

Explanation:

Iteration is a repetative process, where process is repeated until it get closer to the desired result. It is important to inform the team member without wasting much of time, so that they can coordinate or team member can take up another task from the queue. Iteration planning is the collabrative exercise, team work is important as goal and task are set in a team meeting. This is considered as slower process than new algorithm process.

You might be interested in

Solar Hydro manufactures a revolutionary aeration system that combines coarse and fine bubble aeration components. This year (ye

Ierofanga [76]

Answer:

$7,986

Explanation:

To calculate the equivalent annual cost for 5 year period at an interest rate of 10% per year we need to go through some minor calculations first.

DATA

Cost in first year (A) = $10,000

Decrease in cost each year after the first year (G) = $560

Interest rate = 10%

Time period = 5 years

Solution

EAC = A - G (A/G, i, n)

EAC = $9,000 - $560(A/G, 10%, 5)

EAC = $9,000 - ($560 * 1.8101)

EAC = $9,000 - $1,013.656

EAC = $7,986

4 0

1 year ago

Show that if the contribution to profit for trains is between $1.50 and $3, the current basis remains optimal. If the contributi

Dmitriy789 [7]

Answer:

210

Explanation:

Let us consider that x is the number of soldiers produced each week and y is number of trains produced each week.

Also, weekly revenues and costs can be expressed in terms of the decision variables x and y.

Then,

Hence the profit which we want to maximize is given by,

Now the constraints are given as,

Finishing Constraint:

Each week, no more than 100 hours of finishing time may be used.

Carpentry Constraint:

Each week, no more than 80 hours of carpentry time may be used.

Demand Constraint:

Because of limited demand, at most 40 soldiers should be produced each week.

Combining the sign restrictions and with the objective function and constraints,and yield the following optimization model:

Such that,

First convert the given inequalities into equalities:

From equation (1):

If x=0 in equation (1) then (0,100)

If y=0 in equation (1) then (50,0)

From equation (2):

If x=0 in equation (2) then (0,80)

If y=0 in equation (2) then (80,0)

From equation (3):

Equation (3) is the line passing through the point x=40.

Therefore, the given LPP has a feasible solution first image

The optimum solution for the given LPP is obtained as follows in the second image

The optimal solution to this problem is,

And the optimum values are .

Let c be the contribution to profit by each train. We need to find the values of c for which the current, basis remain optimal. Currently c is 2, and each iso-profit line has the form

3x + 2y = constant

y = 3x/2 +constant/ 2

And so, each iso-profit line has a slope of .

From the graph we can see that if a change in c causes the isoprofit lines to be flatter than the carpentry constraint, then the optimal solution will change from the current optimal solution to a new optimal solution, If the profit for each train is c, the slope of each isoprofit line will be.

-3/c

Because the slope of the carpentry constraint is –1, the isoprofit lines will be flatter than the carpentry constraint.

If,

-3/c<-1

c >3

and the current basis will no longer be optimal. The new optimal solution will be point A of the graph.

If the is oprofit lines are steeper than the finishing constraint, then the optimal solution will change from point B to point C. The slope of the finishing constraint is –2.

If,

-3/c < -2 or

C < 1.5

Then the current basis is no longer optimal and point C,(40,20), will be optimal. Hence when the contribution to the profit for trains is between $1.50 and $3, the current basis remains optimal.

Again, consider the contribution to the profit for trains is $2.50, then the decision variables remain the same since the contribution to the profit for trains is between $1.50 and $3. And the optimal solution is given by,

z = 3× (20) + 2.5 × (60)

= 60 + 150

= 210

5 0

2 years ago

The following are nine technical accounting terms introduced or emphasized in this chapter. Responsibility margin Transfer price

Ostrovityanka [42]

Answer: Please refer to Explanation

Explanation:

The terms will be listed in bold at the end of the statement. If you require further clarification please do comment.

a. The costs deducted from the contribution margin to determine the responsibility margin. TRACEABLE FIXED COSTS.

b. Cost to produce plus a predetermined markup. COST-PLUS TRANSFER PRICE

c. Fixed costs that are readily controllable by the manager. NONE

d. A subtotal in a responsibility income statement, equal to responsibility margin plus committed fixed costs. PERFORMANCE MARGIN.

e. The subtotal in a responsibility income statement that is most useful in evaluating the short-run effect of various marketing strategies on the income of the business. CONTRIBUTION MARGIN.

f. The subtotal in a responsibility income statement that comes closest to indicating the change in income from operations that would result from closing a particular part of the business. RESPONSIBILITY MARGIN.

g. The amount used in recording products or services supplied by one business unit to another. TRANSFER PRICE.

5 0

2 years ago

Chubbs Inc.’s manufacturing overhead budget for the first quarter of 2017 contained the following data. Variable Costs Fixed Cos

nydimaria [60]

Answer:

$\left[\begin{array}{cccc}-&Budget&Variance&Actual\\IL&10,000&700&9,300\\IM&11000&-3,800&14,800\\Utilities&7,400&-2,400&9,800\\Maintenance&6,000&1,200&4,800\\Total \: Variable&34,400&-4,300&38,700\\Supervisor&35,400&0&35,400\\Depreciation&7,100&0&7100\\PT and insurance&7,700&-600&8,300\\Maintenance&6,000&0&6,000\\Total \: Fixed&56,200&-600&56,800\\Total \: MO&90,600&-4,900&95,500\\\end{array}\right]$

Explanation:

We list them and subtract budget - actual

When actual is greater than budget the variance is negatine.

While budget being lower than actual is considered a positive variance.

3 0

2 years ago

Project A has a predicted payback period of 2.5 and Project B has a predicted payback period of 5. Based on this information we

anastassius [24]

Answer:

A. more information should be gathered before deciding on which project, if either, is desirable.

Explanation:

The lower Payback Period is not sufficient information to decide which project is more profitable. The payback period indicates when in the life of a project the initial investment principal cash flow is achieved.

But to decide about a certain project it is better to know the interest yield, it is also important to get the life of the project and other information.

For example:

a.- 250 investment 100 per year payback in 2.5-year life 3 years

b.- 500 investment 100 per year payback in 5-year life 20 years

While A payback occurs before project B is better

6 0

2 years ago