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almond37 [142]
2 years ago
6

A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns shown below, making

the one-day sale price of the ski set. The ski set was 10% off and with an extra 30% off.
Mathematics
1 answer:
Akimi4 [234]2 years ago
8 0

The complete question is:

A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns​ shown, making the​ one-day sale price of the ski set ​$325. Find the original selling price of the ski set. It was marked down 10% and 30%

Answer:

  • <u>original price = $ 515.87</u>

Explanation:

<u>1. Data:</u>

a) Final price of the ski set: $ 325

b) First mark down: 10%

c) Second mark down: 30%

d) Original selling price: ?

<u>2. Procedure:</u>

<u />

<u>First mark down</u>:

  • Final price = original price - first mark down - second mark down
  • First mark down = 10% × original price = 0.10 × original price
  • Price after first mark down = original price - 0.10 × original price = 0.90 × original price

<u>Second mark down</u>:

  • Second mark down = 30% × price after first mark down = 0.30 × price after first mark down = 0.30 × 0.90 × original price
  • Price after second mark down = price after first mark down - second mark down
  • Price after second mark down = 0.90 × original price - 0.30 × 0.90 × original price = (1 - 0.30) × 0.90 × original price = 0.70 × 0.90 × original price

<u>Final price</u>:

  • Final price = price after second mark down
  • $ 325 = 0.70 × 0.90 × original price

<u>Simplify and solve for the original price</u>:

  • $325 = 0.63 × original price
  • original price = $325/0.63 = $515.87

<u></u>

<u>Answer: original price = $ 515.87</u>

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YOU DONT HAVE TO DO ALL IF YOU DONT WANT TO JUST DO WHAT YOU CAN
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Answer:

(Warning) Not sure this is completley correct but this is just what I did.

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Part B

Is the relationship for Amit’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

Nonlinear because the line isn’t straight

Part C

Is the relationship between Amit’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

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Part D

Does the data for Camille’s puppy show a function? Why or why not?

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Is the relationship for Camille’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

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Part F

Is the relationship between Camille’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because as the puppy gets older it gains weight.

Part G

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Yes, it does, because each input value has a unique output value. The graph attached ( which shows the data for Camille’s puppy), that each x-value (Weeks) has a unique y-value (Weight in pounds).

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Part H

Is the relationship for Olivia’s puppy’s weight in terms of time linear or nonlinear? Explain your response

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Part I

Is the relationship for Olivia’s puppy’s weight in terms of time increasing or decreasing? Explain your response. Increasing. For every week that goes by, Olivia's puppy is gaining one pound. 6-5= 1  14-13= 1. Gaining a pound every week makes the puppy’s weight increase.

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Which two relationships have a y-intercept and a constant rate of change?

They all have y-intercepts and only Olivia and camilles have a constant rate of change.

Part A

To compare the linear functions, you first need to find their equations. For each of the linear functions, write an equation to represent the puppy’s weight in terms of the number of weeks since the person got the puppy.

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Now you can compare the functions. In each equation, what do the slope and y-intercept represent in terms of the situation?

The y-intercept in the situation is 2/6.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The distance d from one point (x₁, y₁, z₁) to another point (x₂, y₂, z₂) is given by;

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Now from the question;

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The xy-plane is the point where z is 0. i.e

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Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, -7, 0)</em>

d = √[(4 - 4)² + (-7 - (-7))² + (0 - 6)²]

d = √[(0)² + (0)² + (-6)²]

d = √(-6)²

d = √36

d = 6

Hence, the distance to the xy plane is 6 units

<em>(b) The distance from (4, -7, 6) to the yz-plane</em>

The yz-plane is the point where x is 0. i.e

yz-plane = (0, -7, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 6)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 6)²]

d = √[(4)² + (0)² + (0)²]

d = √(4)²

d = √16

d = 4

Hence, the distance to the yz plane is 4 units

<em>(c) The distance from (4, -7, 6) to the xz-plane</em>

The xz-plane is the point where y is 0. i.e

xz-plane = (4, 0, 6).

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d = √[(0)² + (-7)² + (0)²]

d = √[(-7)²]

d = √49

d = 7

Hence, the distance to the xz plane is 7 units

<em>(d) The distance from (4, -7, 6) to the x axis</em>

The x axis is the point where y and z are 0. i.e

x-axis = (4, 0, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 0)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 0)²]

d = √[(0)² + (-7)² + (6)²]

d = √[(-7)² + (6)²]

d = √[(49 + 36)]

d = √(85)

d = 9.22

Hence, the distance to the x axis is 9.22 units

<em>(e) The distance from (4, -7, 6) to the y axis</em>

The x axis is the point where x and z are 0. i.e

y-axis = (0, -7, 0).

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d = √[(4 - 0)² + (-7 - (-7))² + (6 - 0)²]

d = √[(4)² + (0)² + (6)²]

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d = √[(16 + 36)]

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Hence, the distance to the y axis is 7.21 units

<em>(f) The distance from (4, -7, 6) to the z axis</em>

The z axis is the point where x and y are 0. i.e

z-axis = (0, 0, 6).

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d = √(65)

d = 8.06

Hence, the distance to the z axis is 8.06 units

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Answer:

4,962 yards.

Step-by-step explanation:

We are given that,

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Hence, for 15 games, Michael have thrown for 4,962 yards

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