All categories

2 years ago

Malcolm and Ravi raced each other.

Mathematics

1 answer:

Semenov [28]2 years ago

3 0

Malcolm maximum speed is 200 km/h and Ravi maximum speed is 320 km/h

Step-by-step explanation:

Lets assume Malcolm maximum speed to be M km/h and Ravi maximum speed to be R km/h

Average of their maximum speed is; (M+R)/2 =260 km/h

This can be simplified to M+R= 260*2

M+R = 520.......................................(I)

When Malcolm's speed is doubled,

2M=R+80 km/h ----------------------(ii)

The two equations are;

M+R = 520 ------ M=520-R ----(i)

2M=R+80 ---------------------------(ii)

Replacing M with (i) above

2M=R+80

2(520-R) =R+80

1040 -2R =R+80

1040-80 = R+2R

960 = 3R

960/3 =R

320 =R

M+R =520

M=520-320 =200

Malcolm maximum speed is 200 km/h and Ravi maximum speed is 320 km/h

Learn More

Simultaneous equations:brainly.com/question/12919422

Keywords: Average, maximum, speeds, doubled,

#LearnwithBrainly

You might be interested in

A nurse is preparing to administer dextrose 5% water (D5W) 250 ml IV to infuse over 2 hr. The nurse should set the IV pump to de

Molodets [167]

Answer:

the answer is 125

Step-by-step explanation:

I divided 250 and 2

125***ANSWER

4 0

2 years ago

Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when

valentina_108 [34]

Solution:

$f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$

We have to find the remainder when f(x) is divided by $x^2-1.$

x²-1=0

x= $\pm1$

$f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13$

So, remainder is 13 and -13.

5 0

2 years ago

Read 2 more answers

300 reduced by twice a number is 146. what is the number?

Bogdan [553]

300 - 2x = 146, where x is the number

Subtract 300 from both sides.

-2x = -154

Divide both sides by -2.

x = 77

4 0

2 years ago

Read 2 more answers

Choose the function whose graph is given by:

katen-ka-za [31]

Answer:

D. $y=\tan (x-\pi)+2$

Step-by-step explanation:

We are given the graph of the transformed tangent function.

As, we can see that the graph is shifted 2 units upwards.

That is, the parent function is translated 2 units up.

So, the new function will be of the form, $y=\tan (x)+2$ .

Thus, options A and C are not correct.

Moreover, 'If a function f(x) has period P, then the function cf(bx) will have period $\frac{P}{|b|}$ .

Also, form the figure, we see that the period of the graphed function is $\pi$ .

Since, $y=\tan (x)$ have period $\pi$ .

So, function in option B will have period $\frac{\pi}{2}$ , which is not possible.

Further, function in option D have period $\pi$ .

Thus, the equation of the graphed function is, $y=\tan (x-\pi)+2$ .

7 0

2 years ago

Read 2 more answers

Ellie has a delivery van which she is going to deliver boxes each box is a cuboid brain.ly 45cm by 40cm by 35cm the space in the

jek_recluse [69]

Answer:

It will take Ellie 64 minutes to put as many boxes as possible.

Step-by-step explanation:

Let us work with meters.

The dimensions of Ellie's boxes in meters are: 0.45m by 0.40m by 0.35 ( to convert from centimeters to meters we just divide by 100, because 1m =100cm). therefore the volume of each box is:

$V_{box}=0.45m*0.40m*0.35m=0.063m^3$

Now the dimensions of the empty van are 3.6m by 1.6m by 2.1 m, therefore its volume $V_{van}$ is:

$V_{van}=3.6m*1.6m*2.1m=12.096m^3.$

So the amount of boxes that Ellie can put in the van is equal to the volume of the van $V_{van}$ divided by the volume $V_{box}$ of each box:

$\frac{V_{van}}{V_{box}} =\frac{12.096}{0.063}=\boxed{192\:boxes }$

So 192 boxes can be put into the van.

Now Ellie can put 3 boxes in the van in 1 minute, therefore the amount of time it will take her to put 192 boxes into the van will be:

$\frac{192boxes}{3boxes/minute} =\boxed{64\:minutes}$

So it takes Ellie 64 minutes to put as many boxes into the van as she can.

4 0

2 years ago