1) The population
Is the set of all the terms that the teacher taught this semester and which he wrote down on the note cards and put in the paper bag.
2) The sample is every set of five cards that is selected by each student.
3) I think the sample is representative because all ther terms have the same probability of being selected.
Further, given that the cards are replaced every time all the students will face the same population when they are going to select a sample.
<span><span>Comments </span> <span>Report</span></span>
we know that
In an Arithmetic Sequence the difference between one term and the next is a constant
This problem is an Arithmetic Sequence
where
the first term is 
and
the common difference is 
In general we can write an Arithmetic Sequence as a rule
where
a1 is the first term
d is the common difference
so
<u>Find the term a7</u>
![an=a1+d*(n-1)\\ \\ a7=23+(-2)*[7-1]\\ \\\\ a7=23-12\\ \\\\ a7=11](https://tex.z-dn.net/?f=%20an%3Da1%2Bd%2A%28n-1%29%5C%5C%20%5C%5C%20%20a7%3D23%2B%28-2%29%2A%5B7-1%5D%5C%5C%20%5C%5C%5C%5C%20a7%3D23-12%5C%5C%20%5C%5C%5C%5C%20%20%20%20a7%3D11%20%20%20%20%20)
therefore
<u>the answer is</u>
Since:
Density=Mass/Volume
Mass=Volume*Density
Therefore, Volume=Mass/Density
Answer:
A=8.4063
Step-by-step explanation:
Be the functions:
according the graph:
=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%20%3D3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%3D3%28%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%29%3D3%5Blnx-%5Cfrac%7B1%7D%7Bx%7D%5D%281-7%29%3D3%5B%28ln7-ln1%29-%28%5Cfrac%7B1%7D%7B7%7D-1%29%5D%3D3%5B%281.945-0%29-%280.1428-1%29%5D%3D3%2A%281.945%2B0.8571%29%3D3%2A2.8021%3D8.4063u%5E%7B2%7D)
We know that
[surface area ]=2*[area of the base]+[perimeter of the base]*height
area of the base=10*8.7/2-----> 43.5 cm²
perimeter of the base=10*3----> 30 cm
height of the prism=15 cm
[surface area ]=2*[43.5]+[30]*15------->537 cm²
the answer is
<span>the approximate surface area of the prism is 537 cm</span>²
