All categories

2 years ago

Find the sum and difference of 147, 167 and 204, 107.

Mathematics

1 answer:

Ray Of Light [21]2 years ago

5 0

Answer:147,167:diffrence,20 sum:314

204,107:311 sum > diffrene 97

Step-by-step explanation:

add subtarct

You might be interested in

Carla packed this box with 1 centimeter cubes what is the volume of the box

shusha [124]

Answer: $60\ cm^3$

Step-by-step explanation:

<h3> The complete exercise is attached.</h3>

You can observe in the picture attached that the box is a rectangular prism.

The volume of a rectangular prism can be found with this formula:

$V=lwh$

Where "l" is the length, "w" is the width and "h" is the height.

You know that the lenght of each side of those cubes is 1 centimeter. Therefore, you can multiply the number of cubes on each side of the box by 1 centimeter in order to find the lenght, the width and the height of the box:

$l=(4)(1\ cm)=4\ cm\\\\w=(3)(1\ cm)=3\ cm\\\\h=(5)(1\ cm)=5\ cm$

Now you can substitute the lenght, the width and the height of the box into the formula shown at the beginning of the explanation:

$V=(4\ cm)(3\ cm)(5\ cm)$

Finally, evaluating, you get that the volume of the box is:

$V=60\ cm^3$

4 0

2 years ago

jose is choosing a 3-letter password from the letters a,b,c,d. the password cannot have the same letter repeated in it. how many

kvasek [131]

Alright, so we are dealing with permutations. Permutations are the number of combinations in a specific order possible for the set.

There's 4 letters, each one can be paired with 3 other letters, but those letters could be in different orders. To figure out how many variations of each combination there are (aka the number of permutations) use this formula:

$_{n}P_{r}= \frac{n!}{(n-r)!}$

$r=$ number of elements in the subset

$n=$ number of elements in the set

$P=$ permutations of the set

There are only 3 elements in the subset because there is 1 that will not be repeated in each set, and there are 4 elements in the set.

Here's the math:

$_{n}P_{r}= \frac{n!}{(n-r)!}$

$_{4}P_{3}= \frac{4!}{(4-3)!}$

$_{4}P_{3}= \frac{4!}{(1)!}$

$_{4}P_{3}= \frac{4(3)(2)(1)}{1}$

$_{4}P_{3}=24$

There are 24 permutations. I can prove this by showing you the model:

ABCD, ABDC, ACBD, ACDB, ADBC, ADCB are the 6 arrangements possible of the set starting with the letter A. Because there are 4 letters, the total amount of permutations without repeated letters is 4 (letters) times 6 (possible arrangements), which equals 24.

Hope this helps!

Answer: 24 passwords are possible

5 0

2 years ago

The density of a certain material is such that it weighs 1 pound for every 3.5 cups of volume. Express this density in tons per

AnnZ [28]

Answer:

0.02 tons per cubic foot

Step-by-step explanation:

delt math

7 0

2 years ago

Suppose babies born in a large hospital have a mean weight of 3316 grams, and a standard deviation of 324 grams. If 83 babies ar

Anuta_ua [19.1K]

Answer: 0.129

Step-by-step explanation:

Let $\overline{X}$ denotes a random variable that represents the mean weight of babies born.

Population mean : $\mu= \text{3316 grams,}$

Standard deviation: $\text{324 grams}$

Sample size = 83

Now, the probability that the mean weight of the sample babies would differ from the population mean by greater than 54 grams will be :

$P(|\mu-\overline{X}|>54)=1-P(\dfrac{-54}{\dfrac{324}{\sqrt{83}}}$

hence, the required probability = 0.129

5 0

2 years ago

The multiplication law is potentially helpful when we are interested in computing the probability of a. mutually exclusive event

Korvikt [17]

Answer:

b ) the intersection of two events

Step-by-step explanation:

Gary and Steve are both hosting . There are 50 buttons total, 15 buttons are blue and 27 buttons are red. Gary puts all of the buttons into a bag. Steve and Gary both want to wear red buttons.What is the probability ? To solve this problem, you need to understand the Multiplication Rule of Probability.This probability means to find the probability of the intersection of two events, multiply the two probabilities.

Probability of two events occurring that is called intersection of two events. There are two different set of events , called independent and dependent events.

Independent events event is not affected by a previous event.

A dependent event is when one event influences the outcome of another event . To find the intersection of two events, whether they are independent or dependent, multiply the two probabilities together.

3 0

2 years ago