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Sliva [168]
2 years ago
12

Convert to octal. Convert to hexadecimal. Then convert both of your answers todecimal, and verify that they are the same.(a) 111

010110001.0112 (b) 10110011101.112
Computers and Technology
1 answer:
melomori [17]2 years ago
3 0

The given decimal values are converted to octal and hexadecimal.

Explanation:

a. The converted octal value of 111010110001.0112 decimal number is  1473055755061.00557000643334272616

The converted hexadecimal value of 111010110001.0112 decimal number is  19D8B7DA31.02DE00D1B71758E21965

b. The converted octal value of 10110011101.112 decimal number is  113246503335.07126010142233513615

The converted hexadecimal value of  10110011101.112 decimal number is  

25A9A86DD.1CAC083126E978D4FDF4

a. while converting back from octal to decimal the value is 111010110001.01119999999999999989

b. while converting back from octal to decimal the value is

10110011101.11199999999999999973

Hence both the values changes while we convert from octal to decimal.

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Arrays are described as immutable because they cannot be changed once they are defined.  (D on Edge)

Explanation:

It's in the notes and I just took the test (2020)

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What are the two main functions of user accounts in Active Directory? (Choose all that apply.) Allow users to access resources m
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method for user authentication to the network

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An in AD, a user account consists of all the information that includes user names, passwords, and groups. All these information defines a domain user in which a user account has membership access to. With the advanced features of Kerbos, mutual authentication in user accounts to a service is achieved.

3 0
2 years ago
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What are two characteristics of a scalable network? (choose two.)?
vampirchik [111]

The two characteristics of scalable network are such that it can easily grow in size without causing any impact to the current users. This means, increase in network capacity and technical capability will not have any detrimental effects to the users.  Another characteristic of this network is that it can work perfectly with modular devices provided they   support expansion process.


7 0
2 years ago
Megan has written the following rough draft for her assignment. Choose the correct way to complete each sentence. Sarah is creat
atroni [7]

Answer:

I. hatching

II. filter

Explanation:

Sarah is creating an image. She wants to achieve tonal effects with parallel lines by varying their densities and distribution patterns. She will use <u>hatching</u> to do this. She also wants to add special effects on the image. Therefore, she will use <u>filters</u>.

Hatching refers to an art technique in which parallel lines are used to shade by drawing them closely together.

Stippling is an art technique used in the making of patterns by using small dots.

Filters is a technique of changing image characteristics. It is used to change the picture characteristics & to add special effects to an image such as the shade, contrast, tone, brightness etc.

We therefore see that, <u>hatching</u> and <u>filter</u> are the correct answers respectively

3 0
2 years ago
Consider the following skeletal C program: void fun1(void); /* prototype */ void fun2(void); /* prototype */ void fun3(void); /*
natita [175]

Answer:

Check the explanation

Explanation:

a) main calls fun1; fun1 calls fun2; fun2 calls fun3

fun3()                                        d, e, f

fun2()                                        c, d, e

fun1()                                        b, c, d

main()                                        a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

   From the above call stack diagram, it is very clear that the last function call is made to fun3().

   In fun3(), the local variables "d, e, f" of fun3() will be visible

   variable "c" of fun2() will be visible

   variable "b" of fun1() will be visible

   variable "a" of main() will be visible

b) main calls fun1; fun1 calls fun3

fun3()                                        d, e, f

fun1()                                        b, c, d

main()                                        a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

   From the above call stack diagram, it is very clear that the last function call is made to fun3().

   In fun3(), the local variables "d, e, f" of fun3() will be visible

   variable "b, c" of fun1() will be visible

   variable "a" of main() will be visible

c) main calls fun2; fun2 calls fun3; fun3 calls fun1

fun1()                                        b, c, d

fun3()                                        d, e, f

fun2()                                        c, d, e

main()                                        a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

   From the above call stack diagram, it is very clear that the last function call is made to fun1().

   In fun1(), the local variables "b, c, d" of fun1() will be visible

   variable "e, f" of fun3() will be visible

   variable "a" of main() will be visible

d) main calls fun1; fun1 calls fun3; fun3 calls fun2

fun2()                                        c, d, e

fun3()                                        d, e, f

fun1()                                        b, c, d,

main()                                        a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

   From the above call stack diagram, it is very clear that the last function call is made to fun2().

   In fun2(), the local variables "c, d, e" of fun2() will be visible

   variable "f" of fun3() will be visible

     variable "b" of fun1() will be visible

   variable "a" of main() will be visible

The last function called will comprise of all its local variables and the variables other than its local variables from all its preceding function calls till the main function.

8 0
2 years ago
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