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olga_2 [115]
2 years ago
12

Axel is finally documenting his work. What could he be writing?

Computers and Technology
1 answer:
allochka39001 [22]2 years ago
7 0

Answer: maybe his wrtting ezam

Explanation:

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Java uses interfaces to provide the benefits of multiple inheritance. A superclass object is a subclass object. A subclass is of
WITCHER [35]

COMPLETE QUESTION

Which of the following is false?

a. A subclass is often larger than its super class.

b. A super class is object is a subclass object.

c. The class following the extends keyword in a class declaration is that direct super class of the class being declared.

d. Java uses interfaces to provide the benefits of multiple inheritance

Answer:

B) A super class is object is a subclass object.

Explanation:

In object oriented programming, the concept of inheritance is greatly utilized, this refers to deriving a class from another class. The derived class is the sub-class and it is derived from its super class, as a matter of fact in Java programming language, all classes are derived from some other class. Objects are made from classes with their state (fields) and behavior (methods) since objects are made from classes, the objects of the super class will not be the same as that of the subclass.

4 0
2 years ago
Allison wants to use equations to simplify the process of explaining something to the Sales team, but the default eq
yarga [219]

Answer:

Search for something that fits her needs

Explanation:

There are several approaches to problem solving, the approach that will be employed depends on our definition of the problem. Not all processes can be modeled by mathematical equations, some processes are simply theoretical and can be explained by simple logic.

If Allison does not find the needed equations among the available default equations, she can come up with an equation that addresses the process at hand. If she cannot come up with any, she can use other approaches that fit her needs to explain the required concept to the team.

7 0
2 years ago
Read 2 more answers
1.Which of the following class definitions defines a legal abstract class?a. class A { abstract void unfinished() { } }b. class
xxMikexx [17]

Answer:(c) abstract class A { abstract void unfinished(); }

Explanation:

A legal abstract class must have the keyword abstract before the class and an abstract class has abstract functions with the keyword abstract written and a void as the return type.

8 0
2 years ago
Marissa works at a company that makes perfume. She noticed many samples of the perfume were not passing inspection. She conducte
garik1379 [7]
Writing a business letter as if she gets her point across to the head of department then he could change the way they made the perfume so they would pass inspection and standard.
6 0
2 years ago
Read 2 more answers
1. Create a view named customer_addresses that shows the shipping and billing addresses for each customer.
Verdich [7]

Answer:

Answer given below

Explanation:

1.

CREATE VIEW CustomerAddresses AS

SELECT custo. CustomerID, EmailAddress , LastName ,FirstName,

bill.Line1 AS BillLine1, bill.Line2 AS BillLine2, bill.City AS BillCity, bill.State AS BillState, bill.ZipCode AS BillZip,

ship.Line1 AS ShipLine1, ship.Line2 AS ShipLine2, ship.City AS ShipCity, ship.State AS ShipState, ship.ZipCode AS ShipZip

FROM Customers custo , Addresses ship , Addresses bill

WHERE custo. BillingAddressID= bill.AddressID AND custo.ShippingAddressID= ship. AddressID;

2.

SELECT CustomerID, LastName, FirstName, BillLine1 FROM CustomerAddresses;

3.

CREATE VIEW OrderItemProducts

AS

SELECT Orders.OrderID, OrderDate, TaxAmount, ShipDate,

ItemPrice, DiscountAmount, (ItemPrice- DiscountAmount) AS FinalPrice,

Quantity, and (Quantity * (ItemPrice-DiscountAmount)) AS ItemTotal,

ProductName FROM

Orders, OrderItems, Products

WHERE

Orders.OrderID = OrderItems.OrderID AND

OrderItems.ProductID = Products. ProductID;

4.

CREATE VIEW ProductSummary

AS

SELECT distinct

ProductName, COUNT(OrderID) AS OrderCount, SUM(ItemTotal) AS OrderTotal

FROM

OrderItemProducts

GROUP BY ProductName;

5.

SELECT ProductName, OrderTotal

FROM ProductSummary P

WHERE 5> (select count(*) FROM ProductSummary S

WHERE P.OrderTotal<S.OrderTotal)

ORDER BY OrderTotal;

5 0
2 years ago
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