Answer:
The comparison is based on memory organization schemes of contiguous memory allocation and paging with respect to External fragmentation, Internal fragmentation and Ability to share code across processes.
Explanation:
Memory organization schemes of contiguous memory allocation:
Contiguous memory allocation schemes suffers from external fragmentation. The reason is that address space is distributed contiguously and the holes and gaps keep growing when the old processes die and new processes are introduced. The variable size partition suffers from external fragmentation however the fixed size partitions do not suffer from external fragmentation. Contiguous memory allocation with variable size partitions does not encounter an internal fragmentation but with fixed size partitions suffers from internal fragmentation. Contiguous memory allocation does not support sharing code across processes. This is because the virtual memory segment of a process is not fragmented into non-contiguous fine grained blocks.
Paging:
Paging does not encounter external fragmentation as pages are of the fixed or equal size. So this reduces external fragmentation. However paging suffers from internal fragmentation. This is because a process can request more space or it can request for a less space. When page is allocated to the such a process that page is no longer utilized.This results in internal fragmentation because of the wastage of space even when the page has internal space but cannot be fully utilized. Paging allows to share code across processes.
Answer:
Area
Explanation:
The variable name is the best to hold the area of a rectangle is area
plz give brainliest
Answer:
a. The network will not satisfy the customers because the required addresses is 128 but what can be offered is 126.
b. 195.200.0.0/22
Explanation:
195.200.0.0/16
The number of bits to give 512 is 9
2^9=512
2^8=256 which is not up to our expected 320 customers that requires a network ip
Note we have to use a bit number that is equal or higher than our required number of networks.
The number of host per each subnet of the network (195.200.0.0/25) is (2^7)-2= 128-2=126
The network will not satisfy the customers because the required addresses is 128 but what can be offered is 126.
b. 64 customers requires 6 bits to be taken from the host bit to the network bit
i.e 2^6 = 64
195.200.0.0/22
The number of host per each subnet of the network (195.200.0.0/22) is (2^10)-2=1024 - 2 = 1022 hosts per subnet
This network meet the requirement " 64 customers want 128 addresses/customer "
It is ethical for her to do her schoolwork on the computer, but it was unethical to use her allotted time to play games, which led to her having to request more time on the computer. If she wants to play games, she should get her own computer or device to play games on
