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olga_2 [115]
2 years ago
12

Axel is finally documenting his work. What could he be writing?

Computers and Technology
1 answer:
allochka39001 [22]2 years ago
7 0

Answer: maybe his wrtting ezam

Explanation:

You might be interested in
6.4 Predicting Prices of Used Cars. The file ToyotaCorolla.csv contains data on used cars (Toyota Corolla) on sale during late s
Brums [2.3K]

Answer:

Compare the predictions in terms of the predictors that were used, the magnitude of the difference between the two predictions, and the advantages and disadvantages of the two methods.

Our predictions for the two models were very simmilar. A difference of $32.78 (less than 1% of the total price of the car) is statistically insignificant in this case. Our binned model returned a whole number while the full model returned a more “accurate” price, but ultimately it is a wash. Both models had comparable accuracy, but the full regression seemed to be better trained. If we wanted to use the binned model I would suggest creating smaller bin ranges to prevent underfitting the model. However, when considering the the overall accuracy range and the car sale market both models would be

Explanation:

8 0
2 years ago
You have been tasked with building a URL file validator for a web crawler. A web crawler is an application that fetches a web pa
mixas84 [53]

Answer:

Python Code:

def validate_url(url):

#Creating the list of valid protocols and file name extensions

valid_protocols = ['http', 'https', 'ftp']

valid_fileinfo = ['.html', '.csv', '.docx']

#splitting the url into two parts

url_split = url.split('://')

isProtocolValid = False

isFileValid = False

#iterating over the valid protocols and file names for validity

for x in valid_protocols:

if x in url_split[0]:

isProtocolValid = True

break

for x in valid_fileinfo:

if x in url_split[1]:

isFileValid = True

break

#Returning the result if the URL has both valid protocol and file extension

return (isProtocolValid and isFileValid)

url = input("Enter an URL: ")

print(validate_url(url))

Explanation:

The image of the output code is attached. Hope it helps.

4 0
1 year ago
#Write a function called string_finder. string_finder should #take two parameters: a target string and a search string. #The fun
adoni [48]

Answer:

I am writing a Python program:

def string_finder(target,search): #function that takes two parameters i.e. target string and a search string

   position=(target.find(search))# returns lowest index of search if it is found in target string

   if position==0: # if value of position is 0 means lowers index

       return "Beginning" #the search string in the beginning of target string

   elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings

       return "End" # returns end

   elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1

       return "Middle" #returns middle        

   else: #if none of above conditions is true return not found

       return "not found"

#you can add an elif condition instead of else for not found condition as:

#elif position==-1    

#returns "not found"

#tests the data for the following cases      

print(string_finder("Georgia Tech", "Georgia"))

print(string_finder("Georgia Tech", "gia"))

print(string_finder("Georgia Tech", "Tech"))

print(string_finder("Georgia Tech", "Idaho"))

Explanation:

The program can also be written in by using string methods.

def string_finder(target,search):  #method definition that takes target string and string to be searched

       if target.startswith(search):  #startswith() method scans the target string and checks if the (substring) search is present at the start of target string

           return "Beginning"  #if above condition it true return Beginning

       elif target.endswith(search):  #endswith() method scans the target string and checks if the (substring) search is present at the end of target string

           return "End" #if above elif condition it true return End

       elif target.find(search) != -1:  #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string

           return "Middle"  #if above elif condition it true return End

       else:  #if none of the above conditions is true then returns Not Found

           return "Not Found"

6 0
1 year ago
Import java.util.scanner; public class sumofmax { public double findmax(double num1, double num2) { double maxval; // note: if-e
jeyben [28]

Here you go,


Import java.util.scanner

public class SumOfMax {

   public static double findMax(double num1, double num2) {

       double maxVal = 0.0;

       // Note: if-else statements need not be understood to

       // complete this activity

       if (num1 > num2) { // if num1 is greater than num2,

           maxVal = num1; // then num1 is the maxVal.

       }

       else { // Otherwise,

           maxVal = num2; // num2 is the maxVal.

       }

       return maxVal;

   }

   public static void main(String[] args) {

       double numA = 5.0;

       double numB = 10.0;

       double numY = 3.0;

       double numZ = 7.0;

       double maxSum = 0.0;

       /* Your solution goes here */

       maxSum = findMax(numA, numB); // first call of findMax

       maxSum = maxSum + findMax(numY, numZ); // second call

       System.out.print("maxSum is: " + maxSum);

       return;

   }

}

/*

Output:

maxSum is: 17.0

*/

6 0
2 years ago
Kayle is building a web form. He has included space where users can input their phone numbers and email addresses. However, he w
Digiron [165]

Answer:

D. javascript

Explanation:

use form validation method bro

8 0
1 year ago
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