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g100num [7]
2 years ago
15

The round trip flight took 3.9 h flying time. The plane traveled the 510 mi to the city at 255 mi/h with no wind. How strong was

the wind on the return flight? Was the wind a head or tail wind?
Mathematics
1 answer:
scoundrel [369]2 years ago
5 0
Let x= speed in mph on the return flight.510/x=time     distace/rate=timeNow to figure time for the first half of the flight.  distance =510 miles, rate was given as 255 mph.  time=510/255 = 2 hours for the first half.  Time for the round triip is given as 3.9h.  Subtract 2 and you find the time for the return trip.3.9-2=1.9.  Since this is less time for the first part you can answer part of problem now.  The wind was a tail wind.Now to the equation 510/x=1.9.1.9x=510x=268.421 mph
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Answer:

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Step-by-step explanation:

The given data is:

x:   3          7         11        14          17

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Now, we find sum summation values, relevant to the formula of exponential regression model, using calculator:

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Now, we use formulae of exponential regression model to find out values of constant:

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b = [(5)(308.1494) - (52)(27.77305)]/[(5)(664) - (52)²]

b = 0.16

Now, for a;

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