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faltersainse [42]
2 years ago
11

In this lab, you use the pseudocode in figure below to add code to a partially created Python program. When completed, college a

dmissions officers should be able to use the Python program to determine whether to accept or reject a student, based on his or her class rank.
start
input testScore, classRank
if testScore >= 90 then
if classRank >= 25 then
output "Accept"
else
output "Reject"
endif
else
if testScore >= 80 then
if classRank >= 50 then
output "Accept"
else
output "Reject"
endif
else
if testScore >= 70 then
if classRank >= 75 then
output "Accept"
else
output "Reject"
endif
else
output "Reject"
endif
endif
endif
stop
Instructions

Study the pseudocode in picture above.

Write the interactive inputstatements to retrieve:

A student’s test score (testScoreString)

A student's class rank (classRankString)

Write the statements to convert the string representation of a student’s test score and class rank to the integer data type (testScoreand classRank, respectively).

The rest of the program is written for you.

Execute the program by clicking the "Run Code" button at the bottom and entering 87for the test score and 60 for the class rank.

Run the program again by entering 60 for the test score and 87 for the class rank.
Computers and Technology
1 answer:
Elza [17]2 years ago
4 0

Answer:

Python code is given below with appropriate comments

Explanation:

#Prompt the user to enter the test score and class rank.

testScore = input()

classRank = input()

#Convert test score and class rank to the integer values.

testScore = int(testScore)

classRank = int(classRank)

#If the test score is greater than or equal to 90.

if(testScore >= 90):

   #If the class rank is greater than or equal to 25,

   #then print accept message.

   if(classRank >= 25):

       print("Accept")

   

   #Otherwise, display reject message.

   else:

       print("Reject")

#Otherwise,

else:

   #If the test score is greater than or equal to 80.

   if(testScore >= 80):

       #If class rank is greater than or equal to 50,

       #then display accept message.

       if(classRank >= 50):

           print("Accept")

       

       #Otherwise, display reject message.

       else:

           print("Reject")

   

   #Otherwise,

   else:

       #If the test score is greater than or equal to

       #70.

       if(testScore >= 70):

           #If the class rank is greater than or equal

           #to 75, then display accept message.

           if(classRank >= 75):

               print("Accept")

           

           #Otherwise, display reject message.

           else:

               print("Reject")

       

       #Otherwise, display reject message.

       else:

           print("Reject")

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vekshin1

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

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solve we get

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and

when f = 0.4 and S = 125 %

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2 years ago
Design a class named Person and its two subclasses named Student and Employee. Make Faculty and Staff subclasses of Employee. A
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Answer:

se explaination

Explanation:

//Design a class named Person

public class Person

{

//A person has a name, address, phone number, and email address.

String name;

String address;

String phone;

String email;

//Constructor with arguments

public Person(String pname,String paddress,String phNum,String pemail)

{

name=pname;

address=paddress;

phone=phNum;

email=pemail;

}

// toString() method to return the name

public String toString()

{

return getClass().getName()+" "+name;

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---------------------------------------------------------

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public class Student extends Person

{

//A student has a class status

//(freshman,sophomore, junior, or senior).

//Define the status as a constant.

final int freshman =1;

final int sophomore =2;

final int junior=3;

final int senior=4;

String status="freshman";

//Constructor with arguments

public Student(String name, String address,String phonenumber, String email, int Status)

{

super(name,address,phonenumber,email);

if(Status == 1)

{

status = "freshman";

}

if(Status == 2)

{

status = "sophomore";

}

if(Status == 3)

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status = "junior";

}

if(Status == 4)

{

status = "Senior";

}

status = "Student";

}

public String toString()

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return super.toString() + " " + status;

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------------------------------------------------------

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public class Employee extends Person

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//An employee has an office, salary, and date hired.

String office;

double salary;

java.util.Date dateHired;

//Constructor with arguments

public Employee(String name,String address,String phonenumber,String email,String off,double sal)

{

super(name,address,phonenumber,email);

office=off;

salary=sal;

}

public String toString()

{

return (super.toString() + " " + office +" " + salary);

}

}

--------------------------------------------------------

//Faculty.java

public class Faculty extends Employee

{

//A faculty member has office hours and a rank.

String officeHours;

String rank;

//Constructor with arguments

public Faculty(String name,String address,String phonenumber,String email,String off,int salary,String offHours,String ranks)

{

super(name,address,phonenumber,email,off,salary);

officeHours=offHours;

rank=ranks;

}

public String toString()

{

return (super.toString() + " " + officeHours +" " + rank);

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}

-----------------------------------------------------------------------------

//Staff.java

public class Staff extends Employee

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String title;

//Constructor with arguments

public Staff(String name,String address,String phonenumber,String email,String off,int salary,String ti t)

{

super(name,address,phonenumber,email,off,salary);

title=ti t;

}

public String toString()

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return (super.toString() + " " + title);

}

}

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A large software development company employs 100 computer programmers. Of them, 45 areproficient in Java, 30 in C, 20 in Python,
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Answer:

18, 13, 19

Explanation:

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Number of computer programmers proficient only in C++ = 30 - (6+1+5) = 18

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