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Georgia [21]
2 years ago
14

A situation where the bones are connected exclusively by ligaments, cords, or bands of fibrous tissue is a ________.

Biology
1 answer:
In-s [12.5K]2 years ago
6 0

Answer:

Gomphosis

Explanation:

Fibrous Joints:

Fibrous joints are immovable or fixed joints because they have the characteristic that they do not move. These joints have collagen which is a white connective tissue and it help in connection with other tissues.

Fibrous joints are mainly three types called sutures, gomphosis and syndesmosis.

Suture:

Suture is one of the fibrous tissue which only present in skull called cranal suture. There is tiny amount of movement present it sutures for elasticity of skull.

Gomphosis:

Gomphosis is found in the tooth which bind tooth with tooth socket bone by periodontal ligament. This joint is completely immovable.

*Peridontal ligament is the fibrous tissue which is present between tooth and tooth socket.

Syndesmosis:

Syndesmosis is found between tibia and fibula joint which is joined or connected by connective tissue (ligament). This fibrous joint is slightly moveable.

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Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it complet
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Answer:

5.7 m/s     

Explanation:

The computation of Sheila 's velocity right after she gets thrown out of the bike is shown below:

1) The Physical principle: conservation of momentum.

If there is no net external force operating on a system, so the system's total momentum is conserved

The momentum, p, is a vector magnitude that is determined as the product of the mass by the velocity:

P = mv.

2) Taking into account therefore that there is no net force on the device, Sheila and the momentum of the bike are the identical pre and post collision.

Based on this, the calculation is as follows

Momentum before the collision:

       P_1 = (mass\ of\ Sheila + mass\ of\ the\ bike) \times velocity

       P_1 = (60kg + m) \times v_1

= 340 kg m/s

Now Momentum after the collision:

      P_2 = mass\ of\ sheila \times velocity\ of\ Sheila + mass\ of\ the\ bike \times velocity\ of\ the\ bike

P_2 = 60kg \times v_2 + m \times 0 = 60kg \times v_2

P_1 = P_2

= (60kg + m) \times v_1

= 60kg \times v_2

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= 60kg \times v_2

v_2 =  \frac{340\ kg .\ m/s }{60\ kg}

= 5.7 m/s     

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2 years ago
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